Description Air Bovinia operates flights connecting the N farms that the cows live on (1 <= N <= 20,000). As with any airline, K of these farms have been designated as hubs (1 <= K <= 200, K <= N). Currently, Air Bovinia offers M one-way fl…
4097: [Usaco2013 dec]Vacation Planning Description Air Bovinia is planning to connect the N farms (1 <= N <= 200) that the cows live on. As with any airline, K of these farms (1 <= K <= 100, K <= N) have been selected as hubs. The farms are…
Problem 2. Fruit Feast 很简单的智商题(因为碰巧脑出来了所以简单一,一 原题: Bessie has broken into Farmer John's house again! She has discovered a pile of lemons and a pile of oranges in the kitchen (effectively an unlimited number of each), and she is determined to eat as m…
Description Air Bovinia is planning to connect the N farms (1 <= N <= 200) that the cows live on. As with any airline, K of these farms (1 <= K <= 100, K <= N) have been selected as hubs. The farms are conveniently numbered 1..N, with farms…
1.Circular Barn http://www.usaco.org/index.php?page=viewproblem2&cpid=621 贪心 #include <cstdio> #include <vector> #include <algorithm> #include <cstring> using namespace std; long long sum(long long v) { )*(*v+)/; } int main()…
Problem 1. Empty Stalls 扫两遍即可. Problem 2. Line of Sight 我们发现能互相看见的一对点一定能同时看见粮仓的某一段.于是转换成有n段线段,问有多少对线段相交.可以按左端点排序,用优先队列维护右端点,弹出比左端点小的. 为了方便计算对数,我们可以先做一遍,再把每个线段都+2*pi,再计数. Problem 3. No Change (没有看到要买的东西必须是依次的..) 如果要依次买的话就显然可以用dp搞.…
