<?php /*** * 单链表 */ //节点,下标,节点名称,下一个节点的地址 class Node { public $id; public $name; public $next; public function __construct($id, $name) { $this->id = $id; $this->name = $name; $this->next = null; } } class SingleLinkList { private $header; publ…

题干: You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two num…

You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. Input: (2 -> 4 -> 3) + (5 -> 6 ->…

https://leetcode.com/problems/add-two-numbers/ You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked…

You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers…

这个很多基础算法,python已内部实现了. 所以,要想自己实现链表这些功能时, 反而需要自己来构造链表的数据结构. 当然,这是python灵活之处, 也是python性能表达不如意的来源. value_list = [1, 5, 6, 2, 4, 3] pointer_list = [3, 2, -1, 5, 1, 4] head = 0 print(value_list[head]) next_pointer = pointer_list[head] while next_pointer !…

题意:两个非空链表求和,这两个链表所表示的数字没有前导零,要求不能修改原链表,如反转链表. 分析:用stack分别存两个链表的数字,然后从低位开始边求和边重新构造链表. Input: (7 -> 2 -> 4 -> 3) + (5 -> 6 -> 4) Output: 7 -> 8 -> 0 -> 7 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListN…

# Definition for singly-linked list. class ListNode(object): def __init__(self, x): self.val = x self.next = None class Solution(object): def addTwoNumbers(self, l1, l2): l3 = ListNode() current = l3 carry = , | None, | ,None # Pad if None if l1 is N…

目录 LeetCode 单链表专题 <c++> \([2]\) Add Two Numbers \([92]\) Reverse Linked List II \([86]\) Partition List \([82]\) Remove Duplicates from Sorted List II \([61]\) Rotate List \([19]\) Remove Nth Node From End of List LeetCode 单链表专题 <c++> \([2]\)…

使用java代码模拟单链表的增删改以及排序功能 代码如下: package com.seizedays.linked_list; public class SingleLinkedListDemo {// 主方法 public static void main(String[] args) { HeroNode node1 = new HeroNode(1, "宋江", "及时雨"); HeroNode node2 = new HeroNode(2, "卢…