[LeetCode]Palindrome Number 推断二进制和十进制是否为回文

【[LeetCode]Palindrome Number 推断二进制和十进制是否为回文】的更多相关文章

[LeetCode]Palindrome Number 推断二进制和十进制是否为回文

class Solution { public: bool isPalindrome2(int x) {//二进制 int num=1,len=1,t=x>>1; while(t){ num<<=1; t>>=1; len++; } len/=2; while(len--){ if((num&x==0)&&(x&1)!=0){ return 0; } x&=(~num); x>>=1; num>>=2; }…

9. Palindrome Number(判断整型数字是否是回文，直接暴力即可)

Determine whether an integer is a palindrome. Do this without extra space. class Solution: def isPalindrome(self, x): """ :type x: int :rtype: bool """ x =str(x) for i in range(int(len(x)/2)+1): if(x[i]!=x[len(x)-i-1]): retur…

[LeetCode]Palindrome Partitioning 找出所有可能的组合回文

给定一个字符串,切割字符串,这样每个子字符串是一个回文字符串. 要找出所有可能的组合. 办法:暴力搜索+回溯 class Solution { public: int *b,n; vector<vector<string> >ans; void dfs(int id,string &s,int len){ if(id>=n){ if(len>0){ vector<string>vt; vt.push_back(s.substr(0,b[0]+1));…

[LeetCode] Palindrome Number 验证回文数字

Determine whether an integer is a palindrome. Do this without extra space. click to show spoilers. Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the restriction of using ext…