Two elements of a binary search tree (BST) are swapped by mistake.Recover the tree without changing its structure.Note:A solution using O(n) space is pretty straight forward. Could you devise a constant space solution?二叉排序树中有两个节点被交换了,要求把树恢复成二叉排序树.最简单…

Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST. No…

Given the root node of a binary search tree (BST) and a value. You need to find the node in the BST that the node's value equals the given value. Return the subtree rooted with that node. If such node doesn't exist, you should return NULL. For exampl…

给定一个有相同值的二叉搜索树(BST),找出 BST 中的所有众数(出现频率最高的元素). 假定 BST 有如下定义: 结点左子树中所含结点的值小于等于当前结点的值 结点右子树中所含结点的值大于等于当前结点的值 左子树和右子树都是二叉搜索树 例如: 给定 BST [1,null,2,2], 1 \ 2 / 2 返回[2]. 提示:如果众数超过1个,不需考虑输出顺序 class Solution { public: map<int, int> check; int MAX = 0; vector…

给定二叉搜索树(BST)的根节点和一个值. 你需要在BST中找到节点值等于给定值的节点. 返回以该节点为根的子树. 如果节点不存在,则返回 NULL. class Solution { public: TreeNode* searchBST(TreeNode* root, int val) { if(root == NULL) return NULL; if(root ->val == val) return root; else if(root ->val > val) return…

Recover Binary Search Tree Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Note: A solution using O(n) space is pretty straight forward. Could you devise a constant space solution? c…

Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Note:A solution using O(n) space is pretty straight forward. Could you devise a constant space solution? confused what "{1,#,2,3}"…

Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Note: A solution using O(n ) space is pretty straight forward. Could you devise a constant space solution? confused what"{1,#,2,3}&quo…

原题地址:https://oj.leetcode.com/problems/recover-binary-search-tree/ 题意: Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. 解题思路:这题是说一颗二叉查找树中的某两个节点被错误的交换了,需要恢复成原来的正确的二叉查找树. 算法一:思路很简单,一颗二叉查…

[题目] Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Note:A solution using O(n) space is pretty straight forward. Could you devise a constant space solution? confused what "{1,#,2,3}…