Single Number III Given 2*n + 2 numbers, every numbers occurs twice except two, find them. Example Given [1,2,2,3,4,4,5,3] return 1 and 5 Challenge O(n) time, O(1) extra space. 可耻的百度了..点这里 还是好理解的.当然不一定要用最低位的1,任意找一个1即可.不过有lowbit = xor & -xor 这个公式当然是这个…