hdu 4258 斜率DP】的更多相关文章

思路:dp[i]=dp[j]+(num[i]-num[j+1])^2; #include<iostream> #include<cstring> #include<algorithm> #include<cstdio> #define Maxn 1000010 #define LL unsigned __int64 using namespace std; LL dp[Maxn],num[Maxn]; ]; inline int ReadInt() { ch…
B - Lawrence HDU - 2829 这个题目我觉得很难,难在这个dp方程不会写. 看了网上的题解,看了很久才理解这个dp转移方程 dp[i][j] 表示前面1~j 位并且以 j 结尾分成了 i 段的最小权值和 再定义一个数组 w[a,b] 表示 a到b 的权值和,注意这个不是前缀和,而是题目给的那种权值和 比如 a 到 b  是4 5 1 2 Its Strategic Value is 4*5 + 4*1 + 4*2 + 5*1 + 5*2 + 1*2 = 49. w[a,b]=4…
不好理解,先多做几个再看 此题是很基础的斜率DP的入门题. 题意很清楚,就是输出序列a[n],每连续输出的费用是连续输出的数字和的平方加上常数M 让我们求这个费用的最小值. 设dp[i]表示输出前i个的最小费用,那么有如下的DP方程: dp[i]= min{ dp[j]+(sum[i]-sum[j])^2 +M }  0<j<i 其中 sum[i]表示数字的前i项和. 相信都能理解上面的方程. 直接求解上面的方程的话复杂度是O(n^2) 对于500000的规模显然是超时的.下面讲解下如何用斜率…
D - Pearls HDU - 1300 这个题目也是一个比较裸的斜率dp,依照之前可以推一下这个公式,这个很好推 这个注意题目已经按照价格升序排列序,所以还是前缀和还是单调的. sum[i] 表示前面 i 种珍珠的花费的前缀和 dp[i]表示买前面 i 种珍珠需要的最少的花费 dp[i]=min(dp[j]+(sum[i]-sum[j]+10)*c[i] j>k 如果要求选 j  更优,则需要满足下列式子 dp[j]+(sum[i]-sum[j]+10)*c[i]<dp[k]+(sum[i…
思路:dp[i][x]=dp[j][x-1]+val[i]-val[j]-sum[j]*sum[i]+sum[j]*sum[j]; 其中val[i]表示1~~i是一段的权值. 然后就是普通斜率dp做法. #include<cstdio> #include<iostream> #include<cstring> #include<algorithm> #include<cstring> #define Maxn 1010 #define LL __…
Covered Walkway Time Limit: 30000/10000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 1496    Accepted Submission(s): 602 Problem Description Your university wants to build a new walkway, and they want at least p…
Division Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 999999/400000 K (Java/Others)Total Submission(s): 5053    Accepted Submission(s): 1980 Problem Description Little D is really interested in the theorem of sets recently. There’s a prob…
思路:直接通过斜率优化进行求解. #include<iostream> #include<cstdio> #include<algorithm> #include<cmath> #include<cstring> #define Maxn 1000010 using namespace std; __int64 sum[Maxn]; __int64 num[Maxn]; ]; int main() { int n,k,head,rear,x; i…
Covered Walkway Problem Description   Your university wants to build a new walkway, and they want at least part of it to be covered. There are certain points which must be covered. It doesn’t matter if other points along the walkway are covered or no…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3480 Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 999999/400000 K (Java/Others) Little D is really interested in the theorem of sets recently. There’s a problem that confused him a long time.   …