LintCode-53.翻转字符串】的更多相关文章

题目: 翻转字符串 给定一个字符串,逐个翻转字符串中的每个单词. 样例 给出s = "the sky is blue",返回"blue is sky the" 说明 单词的构成:无空格字母构成一个单词 输入字符串是否包括前导或者尾随空格?可以包括,但是反转后的字符不能包括 如何处理两个单词间的多个空格?在反转字符串中间空格减少到只含一个 解题: 这个题目方法很多的 1.整体反转,对每个单词再反转,但是中间的多个空格还有单独处理 2.把后面的单词,拿到前面去.参考程序…
Write a function that takes a string as input and reverse only the vowels of a string. Example 1:Given s = "hello", return "holle". Example 2:Given s = "leetcode", return "leotcede". 这道题让我们翻转字符串中的元音字母,元音字母有五个a,e,i,o…
Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". Update (2015-02-12): For C programmers: Try to solve it in-place in O(1) space. click to show clarification. Cl…
1.2 Implement a function void reverse(char *str) in C or C++ which reverses a null-terminated string. 这道题让我们用C++或C语言来翻转一个字符串,不算一道难题,在之前那道Reverse Words in a String 翻转字符串中的单词中用到了这个函数,跟那道题比起来,这题算简单的了.C语言的版本要比C++的稍微复杂一些,应为string类集成了很多有用的功能,比如得到字符串的长度,用下标…
Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: "Let's take LeetCode contest" Output: "s'teL ekat edoCteeL tsetnoc"…
Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters left, reverse all of them. If there are less than 2k but greater than or eq…
Given an input string, reverse the string word by word. Example: Input: "the sky is blue", Output: "blue is sky the". Note: A word is defined as a sequence of non-space characters. Input string may contain leading or trailing spaces. H…
版权声明: 本文为博主Bravo Yeung(知乎UserName同名)的原创文章,欲转载请先私信获博主允许,转载时请附上网址 http://blog.csdn.net/lzuacm. C#版 - Leetcode 151. 翻转字符串里的单词 - 题解 151.Reverse Words in a String 在线提交: https://leetcode-cn.com/problems/reverse-words-in-a-string/ 题目描述 给定一个字符串,逐个翻转字符串中的每个单词…
题目: 给定一个字符串,逐个翻转字符串中的每个单词. 示例 1: 输入: "the sky is blue" 输出: "blue is sky the" 示例 2: 输入: "  hello world!  " 输出: "world! hello" 解释: 输入字符串可以在前面或者后面包含多余的空格,但是反转后的字符不能包括. 示例 3: 输入: "a good   example" 输出: "e…
翻转字符串 给定一个字符串,逐个翻转字符串中的每个单词. 说明 单词的构成:无空格字母构成一个单词 输入字符串是否包括前导或者尾随空格?可以包括,但是反转后的字符不能包括 如何处理两个单词间的多个空格?在反转字符串中间空格减少到只含一个 标签 字符串处理 code class Solution { public: /** * @param s : A string * @return : A string */ string reverseWords(string s) { // write y…