The question: Single Number Given an array of integers, every element appears twice except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? My analysis: Thi…
https://leetcode.com/problems/single-number/ Given an array of integers, every element appears twice except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?…
题目描述(面试常考题) 借助了异或的思想 class Solution { public: int singleNumber(vector<int>& nums) { ; ; i < nums.size() ; i++) ret = ret ^ nums[i]; return ret; /* 出现3次的情况借助了位运算的思想,相同的数 则 在int型的各32位都相等,所以32位中各位求和取余就可以得到结果 */ class Solution { public: int singl…
[LeetCode]137. Single Number II 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/single-number-ii/description/ 题目描述: Given an array of integers, every element appears three times except for one, which appears exactly once. Find that singl…
Single Number II Given an array of integers, every element appears threetimes except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 解法一:开辟map记录次数 class So…
一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complex…
题目: Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 题解: The code seems tricky and hard…
Given a non-empty array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? Example 1: Input: [2,2,1] Output:…
问题描述:给出一个整数数组,除了一个元素外,其他每个元素都出现了2次,找出只出现1次的元素. int singleNumber(vector<int>& nums); 分析:比较自然的想法是用一个容器来进行插入.查找.删除操作.遍历nums,先查找容器中是否包含该元素,是则插入,否则删除.最后容器中只剩下只出现1次的元素. 解法: int singleNumber(vector<int>& nums) { int i = 0; unordered_set<in…
一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find >the two elements that a…
