2014多校9 1011 http://acm.hdu.edu.cn/showproblem.php?pid=4970 Killing Monsters Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 331    Accepted Submission(s): 198 Problem Description Kingdom Rush…

Killing Monsters Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 1158 Accepted Submission(s): 527 Problem Description Kingdom Rush is a popular TD game, in which you should build some towers to p…

Codeforces Round #262 (Div. 2) C C - Present C. Present time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Little beaver is a beginner programmer, so informatics is his favorite subject. Soon…

Killing Monsters Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 1993 Accepted Submission(s): 765 Problem Description Kingdom Rush is a popular TD game, in which you should build some towers to…

转载请注明出处: http://www.cnblogs.com/fraud/          ——by fraud Always an integer Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Combinatorics is a branch of mathematics chiefly concerned with counting discrete objects. For instanc…

题意: 有数列a[ ]; 操作op[ ] = { l, r, d }; 询问q[ ] = { x, y }; 操作表示对a的[ l, r ] 区间上每个数增加d; 询问表示执行[ x, y ]之间的op. 打印最终数列. 思路: 用两次差分数列, 先处理出对于每个op调用了几次, 再对数列执行操作. #include <cstdio> #include <cstring> #include <algorithm> using namespace std; const i…

Killing Monsters Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 2838    Accepted Submission(s): 1068 Problem Description Kingdom Rush is a popular TD game, in which you should build some towe…

题意: 给出n项的数列A[ ], q个询问, 询问 [ l, r ] 之间项的和. 求A的全排列中该和的最大值. 思路: 记录所有询问, 利用差分数列qd[ ], 标记第 i 项被询问的次数( 每次区间增1 ). 最后对qd, A 进行升序排序, 对应项相乘, 求和. 理由是: 越大的数被询问覆盖的次数越多那么总和就越大. 差分数列简单易用. #include <cstdio> #include <cstring> #include <algorithm> using…

pid=4970">Killing Monsters                                                                        Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Problem Description Kingdom Rush is a popular TD game, in which…

题意 数轴上有n个点,有m座炮塔,每个炮塔有一个攻击范围和伤害,有k个怪物,给出他们的初始位置和血量,问最后有多少怪物能活着到达n点.n<=100000 分析 对于某个怪物,什么情况下它可以活着到达N点? 对于每个怪物,求他出现的位置到结尾的这段区间的炮塔的伤害总和,如果它的血量大于这个和,那么它就可以活着到达N点. 也就是说,先更新m个区间的值,然后对于每个怪物求一个后缀和. 想到了什么?线段树?树状数组?不存在的.差分就可以解决这个题.因为这个题区间更新和查询时分开的,所以不需要动态的进行修…