Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify th…

［抄题］: Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Example 1: Input: [1,3…

1. 把数组中的 0 移到末尾 283. Move Zeroes (Easy) Leetcode / 力扣 class Solution { public void moveZeroes(int[] nums) { int id=0; for(int num:nums){ if(num!=0)nums[id++]=num; } while(id<nums.length){ nums[id++]=0; } } } 跨计算节点 2. 改变矩阵维度 566. Reshape the Matrix (E…

Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate element must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify t…

287. Find the Duplicate Number   hard http://www.cnblogs.com/grandyang/p/4843654.html 51. N-Queens http://blog.csdn.net/linhuanmars/article/details/20667175  http://www.cnblogs.com/grandyang/p/4377782.html 思路就是利用一个pos[row]=col来记录 行号:row,Queen在第col列.…

Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify th…

Description: Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must…

Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify th…

Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify th…

Question Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not …

Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Example 1: Input: [1,3,4,2,2…

问题描述: Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not mod…

后面3个题都是限制在1-n的,所有可以不先排序,可以利用巧方法做.最后两个题几乎一模一样. 217. Contains Duplicate class Solution { public: bool containsDuplicate(vector<int>& nums) { int length = nums.size(); ) return false; sort(nums.begin(),nums.end()); ;i < length;i++){ ]) return tr…

题目 Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify…

Leetcode之二分法专题-287. 寻找重复数(Find the Duplicate Number) 给定一个包含 n + 1 个整数的数组 nums,其数字都在 1 到 n 之间(包括 1 和 n),可知至少存在一个重复的整数.假设只有一个重复的整数,找出这个重复的数. 示例 1: 输入: [1,3,4,2,2] 输出: 2 示例 2: 输入: [3,1,3,4,2] 输出: 3 说明: 不能更改原数组(假设数组是只读的). 只能使用额外的 O(1) 的空间. 时间复杂度小于 O(n2)…

Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Example 1: Input: [1,3,4,2,2…

传送门 Description Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You mu…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 保存已经访问过的数字 链表成环 二分查找 日期 题目地址:https://leetcode.com/problems/find-the-duplicate-number/description/ 题目描述 Given an array nums containing n + 1 integers where each integer is betwe…

最容易想到的思路是新开一个长度为n的全零list p[1~n].依次从nums里读出数据,假设读出的是4, 就将p[4]从零改成1.如果发现已经是1了,那么这个4就已经出现过了,所以他就是重复的那个数.这个解法的时间复杂度是O(N).但是由于本题要求空间复杂度是O(1).所以不能用. 可以用二分法,low = 1, high = n, mid = (left + right)//2,如果<=mid 的元素个数 > mid,那么重复的数字一定在[1, mid]区间内.反之,则一定在[mid+1,…

Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify th…

python数组和矩阵使用总结 1.数组和矩阵常见用法 Python使用NumPy包完成了对N-维数组的快速便捷操作.使用这个包,需要导入numpy. SciPy包以NumPy包为基础,大大的扩展了numpy的能力.因此只要导入了scipy,不必在单独导入numpy了!为了使用的方便,scipy包在最外层名字空间中包括了所有的numpy内容. 本文还是区分numpy中实现的和scipy中实现的. 以下默认已经:import numpy as np 以及 impor scipy as sp num…

Difficulty:medium  More:[目录]LeetCode Java实现 Description Given an array nums containing n + 1 integers where each integer is between 1 and n(inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate numbe…

总结: 首先 import numpy as np A = np.random.randint(1,100,size = (4,5)) >>A>>array([[56, 96, 27, 38, 33],       [86, 64, 52, 21, 66],       [97, 84, 94, 20, 82],       [65, 17, 77,  9, 17]]) 通常情况下,列表.元组.字典采用len(A),而数组.矩阵采用np.size(A)或A.size.…

转自 :  http://blog.csdn.net/u011253874/article/details/43115447 <span style="font-size:14px;">#R语言备忘录三# #数组array和矩阵matrix.列表list.数据框dataframe #数组 #数组的重要属性就是dim,维数 #得到4*5的矩阵 z <- 1:12 dim(z) <- c(3,4) z #构建数组 x <- array(1:20, dim = …

Leetcode 566. Reshape the Matrix 矩阵变形(数组,模拟,矩阵操作) 题目描述 在MATLAB中,reshape是一个非常有用的函数,它可以将矩阵变为另一种形状且保持数据不变. 已知一个由二维数组表示的矩阵,和两个正整数r(行),c(列),将这个二维数组变换为r*c的矩阵. 如果不能由原矩阵转换为r*c的矩阵就输出原矩阵,否则输出转换后的矩阵. 测试样例 Input: nums = [[1,2], [3,4]] r = 1, c = 4 Output: [[1,2,…

Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Note: You must not modify th…

LeetCode 287. Find the Duplicate Number 暴力解法 时间 O(nlog(n)),空间O(n),按题目中Note"只用O(1)的空间",照理是过不了的,但是可能判题并没有卡空间复杂度,所以也能AC. class Solution: # 基本思路为,将第一次出现的数字 def findDuplicate(self, nums: List[int]) -> int: s = set() for i in nums: a = i in s if a…

Level:   Medium 题目描述: Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Exampl…

今天做图像处理时,看到一个矩阵的处理,简要谈谈下面几段代码: 首先是介绍矩阵(说明:在matlab中无是数组还是矩阵都是按列来存储的) 首先是一些特殊矩阵的建立 zeros(m,n)%建立全0矩阵 ones(m,n)%建立全1矩阵 eye(m,n)%建立对角线全为1 的矩阵 rand(m,n)%(0,1)随机分布的矩阵 randn(m,n)%相比上一个,均值为0,方差为1 magic(m,n)%魔方矩阵 对于矩阵的建立和元素访问,很多和前面介绍的数组相同 下面看图访问矩阵 访问矩阵元素可以用单下…

Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. Example 1: Input: [1,3,4,2,2…