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题意:你有a个黄水晶和b个蓝水晶,要求要x个黄水晶球(2黄),y个绿水晶球(1黄1蓝),z个蓝水晶球(3蓝),问还要多少水晶题解:模拟 C++ Code: #include<cstdio> using namespace std; long long y,b,ny,ng,nb,ans=0; long long max(long long a,long long b){return a>b?a:b;} int main(){ scanf("%I64d%I64d",&am…
传送门:http://codeforces.com/contest/912/problem/A A. Tricky Alchemy time limit per test1 second memory limit per test256 megabytes Problem Description During the winter holidays, the demand for Christmas balls is exceptionally high. Since it's already…
[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] 统计需要的个数. 不够了,就买. [代码] #include <bits/stdc++.h> #define ll long long using namespace std; ll a,b,x,y,z,ta,tb; int main(){ #ifdef LOCAL_DEFINE freopen("rush_in.txt", "r", stdin); #endif ios::sync_w…
Codeforces Round #456 (Div. 2) A. Tricky Alchemy 题目描述:要制作三种球:黄.绿.蓝,一个黄球需要两个黄色水晶,一个绿球需要一个黄色水晶和一个蓝色水晶,一个蓝球需要三个蓝色水晶,现有\(A\)个黄色水晶和\(B\)个蓝色水晶,要制作\(x\)个黄球,\(y\)个绿球和\(z\)个蓝球,还需要多少个水晶? solution \(max(0, x*2+y-A)+max(0, z*3+y-B)\) 时间复杂度:$ O(1) $ B. New Year's…
A. Tricky Alchemy 传送门:http://codeforces.com/contest/912/problem/A 参考程序如下: #include <stdio.h> #include <stdint.h> int main(void) { int64_t a, b, x, y, z; scanf("%I64d%I64d%I64d%I64d%I64d", &a, &b, &x, &y, &z); int6…
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原文:http://www.cnblogs.com/flash3d/archive/2012/01/30/2332158.html ================================================== 源码:http://files.cnblogs.com/flash3d/alc.rar 前几天研究了Bresenham直线扫描算法.颇受其一些优化策略的启发,故想将其推广至二次三次已经n次曲线的批量计算.进过一番假设推导证明,具体思路和过程就不和大家讲了,估计我也讲…
裸的近期点对.... D. Tricky Function time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Iahub and Sorin are the best competitive programmers in their town. However, they can't both qualify to an imp…
D. Tricky Function Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 codeforces.com/problemset/problem/429/D Description Iahub and Sorin are the best competitive programmers in their town. However, they can't both qualify to an important contest. The sele…
A. Tricky Sum Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/598/problem/A Description In this problem you are to calculate the sum of all integers from 1 to n, but you should take all powers of two with minus in the sum.…