不跳过任何点的路程=dis(l,l+1)+dis(l+1,l+2)+...+dis(r-2,r-1)+dis(r-1,r) 要跳过一个点i,则要最小化dis(i,i+2)-dis(i,i+1)-dis(i+1,i+2) 于是用线段树支持单点修改.区间查询和以及最小值即可 #include<cstdio> #define N 100010 int n,m,i,j,loc[N][2],vs[N<<2],vm[N<<2];char op[5]; inline int abs(…
3892: [Usaco2014 Dec]Marathon Time Limit: 10 Sec Memory Limit: 128 MBSubmit: 169 Solved: 100[Submit][Status][Discuss] Description Unhappy with the poor health of his cows, Farmer John enrolls them in an assortment of different physical fitness acti…
Search GO 说明:输入题号直接进入相应题目,如需搜索含数字的题目,请在关键词前加单引号 Problem ID Title Source AC Submit Y 1000 A+B Problem 10983 18765 Y 1036 [ZJOI2008]树的统计Count 5293 13132 Y 1588 [HNOI2002]营业额统计 5056 13607 1001 [BeiJing2006]狼抓兔子 4526 18386 Y 2002 [Hnoi2010]Bounce 弹飞绵羊 43…
Cow Marathon Time Limit: 2000MS Memory Limit: 30000K Total Submissions: 3195 Accepted: 1596 Case Time Limit: 1000MS Description After hearing about the epidemic of obesity in the USA, Farmer John wants his cows to get more exercise, so he has com…
Cow Marathon Time Limit: 2000MS Memory Limit: 30000K Total Submissions: 5117 Accepted: 2492 Case Time Limit: 1000MS Description After hearing about the epidemic of obesity in the USA, Farmer John wants his cows to get more exercise, so he has com…