Given an array nums of n integers where n > 1,  return an array output such that output[i] is equal to the product of all the elements of numsexcept nums[i]. Example: Input: [1,2,3,4] Output: [24,12,8,6] Note: Please solve it without division and in…

Given an integers array A. Define B[i] = A[0] * ... * A[i-1] * A[i+1] * ... * A[n-1], calculate B WITHOUT divide operation. Have you met this question in a real interview? Yes Example For A = [1, 2, 3], return [6, 3, 2]. LeetCode上的原题,请参见我之前的博客Product…

Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Solve it without division and in O(n). For example, given [1,2,3,4], return [24,12,8,6]. Fo…

Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Solve it without division and in O(n). For example, given [1,2,3,4], return [24,12,8,6]. Fo…

Given an array nums of n integers where n > 1,  return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Example: Input: [1,2,3,4] Output: [24,12,8,6] Note: Please solve it without division and in…

lc 238 Product of Array Except Self 238 Product of Array Except Self Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Solve it without divis…

题目描述: Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Solve it without division and in O(n). For example, given [1,2,3,4], return [24,12,8,…

剑指offer 66. 构建乘积数组 题目: 给定一个数组A[0, 1, ..., n-1],请构建一个数组B[0, 1, ..., n-1],其中B中的元素B[i] = A[0] * A[1] * ... * A[i-1] * A[i +1] ... A[n-1].不能使用除法. 同leetcode 238 https://leetcode.com/problems/product-of-array-except-self/ 分析: 假如可以利用除法,则利用(A[0]*A[1]*...A[n-…

Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Solve it without division and in O(n). For example, given [1,2,3,4], return [24,12,8,6]. Fo…

Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Solve it without division and in O(n). For example, given [1,2,3,4], return [24,12,8,6]. Fo…

这题看似简单,不过两个要求很有意思: 1.不准用除法:最开始我想到的做法是全部乘起来,一项项除,可是中间要是有个0,这做法死得很惨. 2.空间复杂度O(1):题目说明了返回的那个数组不算进复杂度分析里面 做法:既然不用除法,对于某个数i, result[i] = 0到i - 1的乘积 X   i + 1 到 n - 1的乘积 具体来说,先正向遍历,result[i] 存储的是 0 到i - 1的乘积,再反向遍历,乘上另一半,这就同时满足了时间复杂度和空间复杂度的要求 class Solution…

1. 问题描写叙述 给定一个n个整数的数组(n>1n>1)nums,返回一个数组output,当中的元素outputioutput_i的值为原数组nums中除numsinums_i之外的全部元素的积.比如:nums数组为[1,2,3,4].返回的output数组为[24,12,8,6]. 要求不用除法和时间复杂度为O(n). 2. 方法与思路 这道题假设没有除法的限制的话就非常easy了,先求全部数的乘积,然后除以numsinums_i.考虑一下除数为零的情况,非常好解决. class Sol…

给出一个数组 nums[i](i = 0,1,...,n-1)  输出数组output[i]满足 output[i] = nums[0] * num[1] * num[2] *..*num[i-1] * num[i+1]*... *num[n-1] 要求不能使用除了output之外的大内存,满足时间复杂度O(n), 空间复杂度O(1). 分析下我们可以令dpf[i] = nums[0] * num[1] * num[2] *..*num[i-1] 而 dpb[i] =  num[i+1]*...…

原题 思路: 注意时间复杂度,分别乘积左右两边,可达到O(n) class Solution { public: vector<int> productExceptSelf(vector<int> &nums) { int len = nums.size(); vector<int> res(len, 1); int left = 1, right = 1; for (int j = 1; j < len; j++) { left *= nums[j -…

    题目链接:https://leetcode.com/problems/product-of-array-except-self/ 238. Product of Array Except Self My Submissions Question Total Accepted: 36393 Total Submissions: 87262 Difficulty: Medium Given an array of n integers where n > 1, nums, return an…

11. Container With Most Water https://www.cnblogs.com/grandyang/p/4455109.html 用双指针向中间滑动,较小的高度就作为当前情况的高度,然后循环找容量的最大值. 不管两个指针中间有多少高度的柱子,只管两头,因为两头的才决定最大容量. class Solution { public: int maxArea(vector<int>& height) { if(height.empty()) ; ; ,end = h…

238. Product of Array Except Self     Total Accepted: 41565 Total Submissions: 97898 Difficulty: Medium Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums exc…

Product of Array Except Self Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Solve it without division and in O(n). For example, given [1,2…

转载请注明出处:z_zhaojun的博客 原文地址 题目地址 Product of Array Except Self Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Solve it without division and i…

Product of Array Except Self Given an array nums of n integers where n > 1, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Example: Input: [1,2,3,4] Output: [24,12,8,6] Constraint: It's…

Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Solve it without division and in O(n). For example, given [1,2,3,4], return [24,12,8,6]. 题目…

Product of Array Except Self Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Solve it without division and in O(n). For example, given [1,2…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 解题方法 两次遍历 日期 题目地址:https://leetcode.com/problems/product-of-array-except-self/description/ 题目描述 Given an array of n integers where n > 1, nums, return an array output such that output[i]…

Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Solve it without division and in O(n). For example, given [1,2,3,4], return [24,12,8,6]. pu…

Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Solve it without division and in O(n). For example, given [1,2,3,4], return [24,12,8,6]. 代码…

［抄题］: Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Solve it without division and in O(n). For example, given [1,2,3,4], return [24,12,8,…

Given an array nums of n integers where n > 1,  return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Example: Input: [1,2,3,4] Output: [24,12,8,6] Note: Please solve it without division and in…

网址:https://leetcode.com/problems/product-of-array-except-self/ 参考:https://leetcode.com/problems/product-of-array-except-self/discuss/65622/Simple-Java-solution-in-O(n)-without-extra-space class Solution { public: vector<int> productExceptSelf(vector…

一个长度为 n 的整形数组nums,其中 n > 1,返回一个数组 output ,其中 output[i] 等于nums中除nums[i]以外所有元素的乘积.不用除法 且在O(n)内解决这个问题.例如,输入 [1,2,3,4],返回 [24,12,8,6].进阶:你可以在常数空间复杂度内解决这个问题吗?(注意:出于空间复杂度分析的目的,输出数组不被视为额外空间.)详见:https://leetcode.com/problems/product-of-array-except-self/desc…

题意:给一个序列nums,要求返回一个序列ans,两序列元素个数相同,ans第i个元素就是除了nums[i]之外所有的数相乘之积. 思路:时间O(n),额外空间O(0). 第一次扫一遍,处理nums[0~i-1]的积作为ans[i],这样的ans[i]就得到了i之前所有数之积,那么只剩下i后面所有数之积. 第二次从后往前扫,跟第一次的做法一样,但是这次得开个临时变量存储积了. class Solution { public: vector<int> productExceptSelf(vect…