作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 个人公众号:负雪明烛 本文关键词:合并,有序链表,递归,迭代,题解,leetcode, 力扣,Python, C++, Java 目录 题目描述 题目大意 解题方法 迭代 Python解法 C++解法 Java解法 递归 日期 题目地址:https://leetcode.com/problems/merge-two-sorted-lists/ 题目描述 Merge two sorted…

描述: 合并两个有序链表. 解决: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { if (!l1) return l2; if (!l2) return l1; if (!l1 && !l2) return NULL; ListNode* ret = ); ListNode* now = ret; while (l1 || l2) { if (!l1) { now->next = l2; break; } else if…

这道题是LeetCode里的第21道题. 题目描述: 将两个有序链表合并为一个新的有序链表并返回.新链表是通过拼接给定的两个链表的所有节点组成的. 示例: 输入:1->2->4, 1->3->4 输出:1->1->2->3->4->4 这道题需要考虑的地方挺多的,首先是头节点的处理,还有尾节点的链接问题.对于头节点,我的想法是先对 l1, l2 的值进行比较,然后把 l1 指向头节点值小的,这样保证了 l1 绝对小于等于 l2,也就是说头节点的链接问题…

①英文题目 Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 ②中文题目 将两个有序链表合并为一个新的有序…

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 list顺序合并就可以了 /** * Definitio…

题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 分析: 将两个有序链表合并为一个新的有序链表并返…

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 题意:合并两个排好的链表并返回新的链表. 可以使用归并排序,从两链表的表头,取出结点,比较两值,将较小的放在新链表中.如1->3->5->6和2->4->7->8,先将1放入新链表,然后将3…

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.Example:Input: 1->2->4, 1->3->4Output: 1->1->2->3->4->4详见:https://leetcode.com/problems…

21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists 需要排序!!! [2,4][1] 输出1 2 4 而不是2 4 1  递归版!! class Solution { public ListNode mergeTwo…

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 这道题让我们合并k个有序链表,之前我们做过一道Merge Two Sorted Lists 混合插入有序链表,是混合插入两个有序链表.这道题增加了难度,变成合并k个有序链表了,但是不管合并几个,基本还是要两两合并.那么我们首先考虑的方法是能不能利用之前那道题的解法来解答此题.答案是肯定的,但是需要修改…

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example: Input: [   1->4->5,   1->3->4,   2->6 ] Output: 1->1->2->3->4->4->5->6 这道题让我们合并k个有序链表,最终合并出来的结果也必须是有序的,之前做过一道 M…

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 题目 合并两个链表 思路 用dummy, 因为需要对头结…

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example:Input: [   1->4->5,   1->3->4,   2->6 ] Output: 1->1->2->3->4->4->5->6 思路 这道题最简单的方法就是我们将K个链表中的所有数据都存进数组中,然后对数据进行…

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example:        Input: 1->2->4, 1->3->4              Output: 1->1->2->3->4->4 解决思路:最简单…

合并K个有序链表,并且作为一个有序链表的形式返回.分析并描述它的复杂度. 详见:https://leetcode.com/problems/merge-k-sorted-lists/description/ 实现语言:Java /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ cla…

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 和88. Merge Sorted Array类似,数据…

LeetCode第21题 Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 翻译: 合并两个有序链表并返回…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 个人公众号:负雪明烛 本文关键词:合并,链表,单链表,题解,leetcode, 力扣,Python, C++, Java 题目地址: https://leetcode.com/problems/merge-k-sorted-lists/description/ 题目描述: Merge k sorted linked lists and return it as one sorted li…

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 思路:这题最容易想到的是,(假设有k个链表)链表1.2合并,然后其结果12和3合并,以此类推,最后是123--k-1和k合并.至于两链表合并的过程见merge two sorted lists的分析.复杂度的分析见JustDoIT的博客.算法复杂度:假设每个链表的平均长度是n,则1.2合并,遍历2n个…

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 题目要求: 合并两个有序链表 注意: 不能开辟新的结点空间 解题思路: 1.归并排序,创建一个新的头结点,从头到尾分别遍历两个链表,并依次比较其大小关系,每次将头指针指向小的那个. 2.递归思想(对于为改变链表结构的…

题目:Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 简单题,只要对两个链表中的元素进行比较,然后移动即可,只要对链表的增删操作熟悉,几分钟就可以写出来,代码如下: struct ListNode { int val;…

合并两个有序的list 把排序好的nums2插入nums1中,假设nums1这个vector的空间永远是够的 思路:倒序!! class Solution { public: void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) { , i2 = n - , k = m + n - ; //完成的最终长度为m+n,末尾的index是m+n-1 && i2>=){ //倒…

合并两个有序数组 (easy,1过) 给定两个有序整数数组 nums1 和 nums2,将 nums2 合并到 nums1 中,使得 num1 成为一个有序数组. 说明: 初始化 nums1 和 nums2 的元素数量分别为 m 和 n. 你可以假设 nums1 有足够的空间(空间大小大于或等于 m + n)来保存 nums2 中的元素. 示例: 输入: nums1 = [1,2,3,0,0,0], m = 3 nums2 = [2,5,6], n = 3 输出: [1,2,2,3,5,6] 需…

problem:Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 先合并两个list,再根据归并排序的方法递归合并.假设总共有k个list,每个list的最大长度是n,那么运行时间满足递推式T(k) = 2T(k/2)+O(n*k).根据主定理,可以算出算法的总复杂度是O(nklogk).空间复杂度的话是递归栈的大小O(logk). /** * De…

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example: Input: [   1->4->5,   1->3->4,   2->6 ] Output: 1->1->2->3->4->4->5->6 要合并K个排好序的链表,我用的方法是用一个优先队列每次存K个元素在队列中,根据优…

题目 Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 分析 数据结构与算法的链表章节的典型实例,将两个有序链表合成一个,保持其有序的性质. AC代码 /** * Definition for singly-linked list. * struct ListNod…

https://leetcode.com/problems/merge-two-sorted-lists/ Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 思路: 考察链表操作,没啥说的. AC代码: /** * Definition for singly-lin…

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Hide Tags Linked List /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *ne…

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Input: [ 1->4->5, 1->3->4, 2->6 ] Output: 1->1->2->3->4->4->5->6 题意: 归并k个有序链表. 思路: 用一个最小堆minHeap,将所有链表的头结点放入 新建一个linkedl…

这道题是LeetCode里的第88道题. 题目描述: 给定两个有序整数数组 nums1 和 nums2,将 nums2 合并到 nums1 中,使得 num1 成为一个有序数组. 说明: 初始化 nums1 和 nums2 的元素数量分别为 m 和 n. 你可以假设 nums1 有足够的空间(空间大小大于或等于 m + n)来保存 nums2 中的元素. 示例: 输入: nums1 = [1,2,3,0,0,0], m = 3 nums2 = [2,5,6], n = 3 输出: [1,2,2,…