Stan and Ollie play the game of multiplication by multiplying an integer p by one of the numbers 2 to 9. Stan always starts with p = 1, does his multiplication, then Ollie multiplies the number, then Stan and so on. Before a game starts, they draw an…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. Converting the input string to integer is NOT allowed. You should NOT use internal library su…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 这道题让我们求两个字符串数字的相乘,输入的两个数和返回的数都是以字符串格式储存的,这样做的原因可能是这样可以计算超大数相乘,可以不受int或long的数值范围的约束,那么我们该如何来计算…

/** * @param {string} num1 * @param {string} num2 * @return {string} */ var multiply = function(num1, num2) { num1 = num1.split("").reverse().join(""); num2 = num2.split("").reverse().join(""); var arr = new Array()…

题目链接 Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative 大整数乘法 我们以289*785为例 首先我们把每一位相乘,得到一个没有进位的临时结果,如图中中间的一行红色数字就是临时结果,然后把临时结果从低位起依次进位.对于一个m位整数乘以…

使用numpy时,跟matlab不同: 1.* dot() multiply() 对于array来说,* 和 dot()运算不同 *是每个元素对应相乘 dot()是矩阵乘法 对于matrix来说,* 和 multiply() 运算不同 * 是矩阵乘法 multiply()  是每个元素对应相乘 A B为array   MA MB为matrix multiply(MA, MB)对应元素相乘 dot(MA, MB)矩阵乘法 注意:对应元素相乘时,矩阵大小必须相同:矩阵相乘时,矩阵大小要满足矩阵相乘要…

Multiply Strings Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative.     各个位相乘,保存在数组中,最后再处理进位. 如 123*456     4,5,6      8,10,12         12,15,18…

题目: Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 思路比较简单,不多说啦 几个需要注意的点: 1. 高位多个为0的,需要进行判断 2. 如果乘数为0的话,可以直接跳过,能节省不少时间 3. string 的两个使用 1) 创建有…

7.4 Write methods to implement the multiply, subtract, and divide operations for integers. Use only the add operator. 这道题让我们实现乘法加法和除法,而且规定了只能使用加法.那么我们先来看如何用加法来实现减法,我们知道,减去一个数就等于加上这个数的负数.那么我们先写一个求负数的函数,对于n来说,我们累计n个-1,对于-n来说,我们累计n个1.这样减法的就搞定了,我们再来看乘法,乘…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 解题思路一: BigInteger!!! JAVA实现如下: import java.math.BigInteger; public class Solution { static pu…