Remove all elements from a linked list of integers that have value val. ExampleGiven: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6Return: 1 --> 2 --> 3 --> 4 –> 5 题目要求: 删除链表中包含val的元素结点 解题思路: 重点在于找到第一个非val的头结点,然后遍历链表,依次删除值为…
①英文题目 Remove all elements from a linked list of integers that have value val. Example: Input: 1->2->6->3->4->5->6, val = 6 Output: 1->2->3->4->5 ②中文题目 删除链表中等于给定值 val 的所有节点. 示例: 输入: 1->2->6->3->4->5->6, val =…
Remove all elements from a linked list of integers that have value val. ExampleGiven: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6Return: 1 --> 2 --> 3 --> 4 --> 5 /** * Definition for singly-linked list. * public class Lis…
Remove all elements from a linked list of integers that have value val. ExampleGiven: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6Return: 1 --> 2 --> 3 --> 4 --> 5 ps:这一题感觉没什么技巧可言,选取一个头指针,一个当前指针,一个前向指针.简单的链表操作而已,代码如下: /** *…
Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. 题目要求: 给一有序链表,删除重复的结点,使得每个元素只出现一次. 解题思路: 1.从头到尾遍历链表,如果前后两个结点相同…
237 - Delete Node in a Linked List Write a function to delete a node (except the tail) in a singly linked list, given only access to that node. Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked…
203题是在链表中删除一个固定的值,83题是在链表中删除重复的数值,但要保留一个:82也是删除重复的数值,但重复的都删除,不保留. 比如[1.2.2.3],83题要求的结果是[1.2.3],82题要求的结果是[1,3]. 这种题用递归去做比较方便思考,特别是这种重复的数值.递归就是只遍历当前的节点的情况,之前的不用管,之后的以当前节点为出发点思考问题. 203. Remove Linked List Elements class Solution { public: ListNode* remo…
Question 203. Remove Linked List Elements Solution 题目大意:从链表中删除给定的数 思路:遍历链表,如果该节点的值等于给的数就删除该节点,注意首节点 Java实现: public ListNode removeElements(ListNode head, int val) { ListNode cur = head; while (cur != null) { if (cur.next != null && cur.next.val ==…
Remove Linked List Elements Remove all elements from a linked list of integers that have value val. ExampleGiven: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6Return: 1 --> 2 --> 3 --> 4 --> 5 Credits:Special thanks to @mith…