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题目描述 这是一个炎热的夏天,奶牛贝茜感觉到相当的疲倦而且她也特别懒惰.她要在她的领域中找到一个合适的位置吃草,让她能吃到尽可能多的美味草并且尽量只在很短的距离.奶牛贝茜居住的领域是一个 N×N 的矩阵.在这个的矩阵中,贝茜至多只愿意花上 K 步.她的每一步移动到一个单元格中,她可以走向北,南,东,西四个方向.例如,假设矩阵如下,其中(B)描述了贝茜的初始位置(初始位置在第 3 行第 3 列): * * * * * * *(B) * * * * * * 当 K=2,则贝茜只能达到标有*的位置.…
Cow Pedigrees Silviu Ganceanu -- 2003 Farmer John is considering purchasing a new herd of cows. In this new herd, each mother cow gives birth to two children. The relationships among the cows can easily be represented by one or more binary trees with…
Cow XORAdrian Vladu -- 2005 Farmer John is stuck with another problem while feeding his cows. All of his N (1 ≤ N ≤ 100,000) cows (numbered 1..N) are lined up in front of the barn, sorted by their rank in their social hierarchy. Cow #1 has the highes…
2590: [Usaco2012 Feb]Cow Coupons Time Limit: 10 Sec Memory Limit: 128 MB Submit: 349 Solved: 181 [Submit][Status][Discuss] Description Farmer John needs new cows! There are N cows for sale (1 <= N <= 50,000), and FJ has to spend no more than his bud…
Cow Tours Farmer John has a number of pastures on his farm. Cow paths connect some pastures with certain other pastures, forming a field. But, at the present time, you can find at least two pastures that cannot be connected by any sequence of cow pat…
Description Farmer  John  needs  new  cows! There  are  N  cows  for  sale (1 <= N <= 50,000), and  FJ  has  to  spend  no  more  than  his  budget  of  M  units  of  money (1 <= M <=$10^{14}$). Cow  i  costs $ P_i$  money (1 <=$ P_i$ <=…
题目大意: 输入n 接下来n行描述n头牛的编号num和品种id 得到包含所有id的最短段 输出最短段的编号差 Sample Input 625 726 115 122 320 130 1 Sample Output 4 Hint INPUT DETAILS: There are 6 cows, at positions 25,26,15,22,20,30, with respective breed IDs 7,1,1,3,1,1. OUTPUT DETAILS: The range from…
题目大意: 输入n,n次操作 操作A:在L(左边)或R(右边)插入一个递增的数 操作D:在L(左边)或R(右边)删除m个数 Sample Input 10A LA LA RA LD R 2A RA RD L 1A LA R Sample Output 72568 Hint Input    Resulting Cow Line A L      1A L      2 1A R      2 1 3A L      4 2 1 3D R 2    4 2A R      4 2 5A R    …
旋转坐标系后转化为正方形,$x'=x+y$,$y'=x-y+1000001$,$k'=2k-1$ 两根扫描线从左往右扫 f[i]表示y坐标下边界为i时的价值和 每次加入/删除一个点等价于一段区间加减 然后查询全局最大值 线段树维护扫描线之间的点 #include<cstdio> #include<algorithm> const int E=1000001,N=E*2-1,M=N*4+10; struct P{int x,y,g;}a[100010]; inline bool cm…
Description 题库链接 给以长度为 \(n\) 的字符串,要求每次只能从两边取一个字符,使得取出来之后字典序最小. \(1\leq n\leq 30000\) Solution 将字符串翻转后加在原字符串后,求个后缀排名.直接比较排名来判断取前还是取后. Code #include <bits/stdc++.h> using namespace std; const int N = (30000+5)<<1; char ch[N]; int n, m, x[N<&l…