Matrix 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5671 Description There is a matrix M that has n rows and m columns (1≤n≤1000,1≤m≤1000).Then we perform q(1≤q≤100,000) operations: 1 x y: Swap row x and row y (1≤x,y≤n); 2 x y: Swap column x and c…

Matrix Time Limit: 3000/1500 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 502    Accepted Submission(s): 215 Problem Description There is a matrix M that has n rows and m columns (1≤n≤1000,1≤m≤1000).Then we perf…

Matrix Time Limit: 3000/1500 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Problem Description There is a matrix M that has n rows and m columns (1≤n≤1000,1≤m≤1000).Then we perform q(1≤q≤100,000) operations: 1 x y: Swap row x and ro…

HDU 4920 Matrix multiplication 题目链接 题意:给定两个矩阵,求这两个矩阵相乘mod 3 思路:没什么好的想法,就把0的位置不考虑.结果就过了.然后看了官方题解,上面是用了bitset这个东西,能够用来存大的二进制数,那么对于行列相乘.事实上就几种情况,遇到0都是0了,1 1得1,2 1,1 2得2,2 2得1.所以仅仅要存下行列1和2存不存在分别表示的二进制数.然后取且bitcount一下的个数,就能够计算出对应的数值了 代码: 暴力: #include <cst…

HDU 2686 Matrix 题目链接 3376 Matrix Again 题目链接 题意:这两题是一样的,仅仅是数据范围不一样,都是一个矩阵,从左上角走到右下角在从右下角走到左上角能得到最大价值 思路:拆点.建图,然后跑费用流就可以,只是HDU3376这题,极限情况是300W条边,然后卡时间过了2333 代码: #include <cstdio> #include <cstring> #include <vector> #include <queue>…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2686 Yifenfei very like play a number game in the n*n Matrix. A positive integer number is put in each area of the Matrix.Every time yifenfei should to do is that choose a detour which frome the top left…

matrix Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5569 Description Given a matrix with n rows and m columns ( n+m is an odd number ), at first , you begin with the number at top-left corner (1,1) and you wa…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2119 Matrix Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2205    Accepted Submission(s): 975 Problem Description Give you a matrix(only contains…

原题地址:http://acm.hdu.edu.cn/showproblem.php?pid=5015 解题思路:一看到题目,感觉是杨辉三角形,然后用组合数学做,不过没想出来怎么做,后来看数据+递推思想,感觉可能是矩阵快速幂,可惜一直不知道a*10+3的 +3怎么处理,果然还是图样图森破啊!如果矩阵能搞出来的话,后面的就简单了,真可惜一直到比赛结束也没想出来,看来这种矩阵的题目做的太少了,真后悔线性代数没有认真学.. 今天晚上又想了一会,完全可以把+3那个放到新的一阶矩阵上,值始终等于3,那么对…

Matrix Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3095    Accepted Submission(s): 1428 Problem Description Give you a matrix(only contains 0 or 1),every time you can select a row or a colu…

Matrix Swapping II Time Limit: 9000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1430    Accepted Submission(s): 950 Problem Description Given an N * M matrix with each entry equal to 0 or 1. We can find som…

Matrix multiplication Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Problem Description Given two matrices A and B of size n×n, find the product of them. bobo hates big integers. So you are only asked to find t…

要注意取出来的时候 先取出q的是后面那个矩阵 后取出p的是前面的矩阵 所以是判断 p.a == q.b #include <iostream> #include <stack> #include <cstring> #include <cstdio> using namespace std; struct Matrix{ int a,b; Matrix(,):a(aa),b(bb){} }m[]; stack<Matrix>s; int main…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4920 解题报告:求两个800*800的矩阵的乘法. 参考这篇论文:http://wenku.baidu.com/link?url=261XeEzH-AZkFGPiN63t1nnojoQF50yiuMoviHroGjVXjjRlxFcvWLcws0jgQcmZo4oA9BJcjnPxVreWRu-XXa9zb6r5gUUTxmBXn_qWSsu&qq-pf-to=pcqq.group 我看过了,只是简…

Matrix multiplication Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 1775    Accepted Submission(s): 796 Problem Description Given two matrices A and B of size n×n, find the product of them.…

Matrix Time Limit: 3000/1500 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 853    Accepted Submission(s): 360 Problem Description There is a matrix M that has n rows and m columns (1≤n≤1000,1≤m≤1000) .Then we per…

Problem Description Given a matrix with n rows and m columns ( n+m ,) and you want to go to the number at bottom-right corner (n,m). And you must go right or go down every steps. Let the numbers you go through become an array a1,a2,...,a2k. The cost…

Problem Description Given an N * M matrix with each entry equal to 0 or 1. We can find some rectangles in the matrix whose entries are all 1, and we define the maximum area of such rectangle as this matrix's goodness. We can swap any two columns any…

Matrix multiplication                                                                           Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Problem Description Given two matrices A and B of size n×n, find the…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2686 思路:多线程dp,参考51Nod 1084:http://www.51nod.com/onlineJudge/questionCode.html#!problemId=1084 注:这道题用滚动数组优化反而WA,压到三维即可 代码: #include <bits/stdc++.h> using namespace std; ][],dp[][][]; int main() { int n;…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=2119 解题思路: 处理数据,使用公式最小点覆盖数=最大匹配数,使用匈牙利算法求二分图最大匹配即可. AC代码: #include<stdio.h> #include<string.h> ][],book[],cx[],cy[]; int Maxmatch(); int path(int u); int main() { int i,j; ) { scanf("%d"…

http://acm.hdu.edu.cn/showproblem.php?pid=6314 题意 对于n*m的方格,每个格子只能涂两种颜色,问至少有A列和B行都为黑色的方案数是多少. 分析 参考https://blog.csdn.net/IcePrincess_1968/article/details/81255138 重点在于计算容斥系数. #include <iostream> #include <cstdio> #include <cstdlib> #inclu…

http://acm.hdu.edu.cn/showproblem.php?pid=4313 题意: 给出一棵树,每条边都有权值,其中有几个点是特殊点,现在破坏边还使得这几个特殊点互相不可达,需要使得破坏的边的权值和最小. 思路:解法很妙! 利用并查集,先将每个点分成一个集合,将边按照降序排序,如果该边两边所在的集合没有特殊点或者只有一边有,那么就可以不用删,用并查集合并.如果两边都有特殊点的话,那就只能删处这条边,因为已经排好序了,所以删的边是尽量最小的. #include<iostream>…

各种TEL,233啊.没想到是处理掉0的情况就能够过啊.一直以为会有极端数据.没想到居然是这种啊..在网上看到了一个AC的奇妙的代码,经典的矩阵乘法,仅仅只是把最内层的枚举,移到外面就过了啊...有点不理解啊,复杂度不是一样的吗.. Matrix multiplication Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 640 …

Matrix Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1890    Accepted Submission(s): 1005 Problem Description Yifenfei very like play a number game in the n*n Matrix. A positive integer numbe…

Matrix Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1394    Accepted Submission(s): 758 Problem Description Yifenfei very like play a number game in the n*n Matrix. A positive integer number…

Problem E. Matrix from Arrays Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 501    Accepted Submission(s): 210 Problem Description Kazari has an array $A$ length of $L$, she plans to generat…

Matrix Time Limit: 3000/1500 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 271    Accepted Submission(s): 126 Problem Description There is a matrix M that has n rows and m columns (1≤n≤1000,1≤m≤1000) .Then we per…

Matrix operation Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 907    Accepted Submission(s): 384 Problem Description M_0 is interested in cryptography. Recently he learned the Advanced Encryp…

Matrix multiplication Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 5236    Accepted Submission(s): 2009 Problem Description Given two matrices A and B of size n×n, find the product of them.…