LeetCode OJ：Convert Sorted List to Binary Search Tree（将排序好的链表转换成二叉搜索树）

[Leetcode] Convert sorted list to binary search tree 将排好的链表转成二叉搜索树

---恢复内容开始--- Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 题目要求:转成高度平衡的二叉搜索树. 高度平衡的二叉搜索树:i)左子树和右子树的高度之差的绝对值不超过1; ii)树中的每个左子树和右子树都是AVL树; iii)每个节点都有一个平衡因子(balance factor bf),任一节点的平衡因子是1,0,…

LeetCode OJ：Convert Sorted List to Binary Search Tree（将排序好的链表转换成二叉搜索树）

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 由于对于这个二叉搜索树的要求是其必须是其必须是平衡的,所以应该使用递归.首先找到二叉树的中点.然后由这个中点作为根节点递归的在从左右子树上面取节点构成一颗二叉树.代码如下所示: /** * Definition for singly-linked list. * struct L…

LeetCode OJ——Convert Sorted List to Binary Search Tree

http://oj.leetcode.com/problems/convert-sorted-list-to-binary-search-tree/ 将一个按照元素升序排列的链表转换成BST.根据自身性质“元素升序排列”,再参考将升序排列的数组转换成BST的上一道题目,只需要将对数组的处理方式变成对链表的.还是得好好利用元素已经升序排列这个性质,不用那种纯粹的重新生成一个BST,按照左转.右转.先左转后右转.先右转后左转. #include <iostream> #include <ve…

LeetCode OJ——Convert Sorted Array to Binary Search Tree

http://oj.leetcode.com/problems/convert-sorted-array-to-binary-search-tree/ 将一个升序的数组转换成 height balanced BST高度平衡的二叉搜索树,根据二叉搜索树的特征,所有比根节点小的值,都在根节点的左边,所有比根节点大的值,都在根节点的右边.建立的过程就是一个个的插入.但要求是高度平衡的,即不能是各种偏的那样,否则的话,搜索的代价会增大,最佳的时候是O(height),height balanced的时候…

LeetCode OJ：Convert Sorted Array to Binary Search Tree（将排序好的数组转换成二叉搜索树）

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 讲一个排序好的数组转换成二叉搜索树,这题没想出来,基本上是参考别人的,边界条件应该注意一下: /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *rig…

[LeetCode] 108. Convert Sorted Array to Binary Search Tree 把有序数组转成二叉搜索树

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more th…

[LeetCode] 109. Convert Sorted List to Binary Search Tree 把有序链表转成二叉搜索树

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never diffe…

[Leetcode][JAVA] Convert Sorted Array to Binary Search Tree && Convert Sorted List to Binary Search Tree

Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 很简单的二分法,只要给出Array的开始和结束下标作为参数传入即可. public TreeNode sortedArrayToBST(int[] num) { return constructBST(num,0,nu…

【leetcode】Convert Sorted List to Binary Search Tree

Convert Sorted List to Binary Search Tree Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 可以采用类似于Covert Sorted Array to Binary Search Tree的方法,但是寻找中点对于链表来说效率较低可以采用更高效的递归方式,无需寻找中点注意引用传…

【leetcode】Convert Sorted Array to Binary Search Tree

Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 每次把中间元素当成根节点,递归即可 /** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * Tre…

Leetcode#109 Convert Sorted List to Binary Search Tree

原题地址跟Convert Sorted Array to Binary Search Tree(参见这篇文章)类似,只不过用list就不能随机访问了. 代码: TreeNode *buildBST(ListNode *head, int len) { ) return NULL; ListNode *p = head; ; < len) { p = p->next; leftLen++; } TreeNode *node = new TreeNode(p->val); node->…

leetcode -day19 Convert Sorted List to Binary Search Tree

1. Convert Sorted List to Binary Search Tree Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 分析:将一个升序排列的链表转换为平衡二叉搜索树,採用递归的方式,先找到链表的中点,作为二叉树的根,然后递归求解左右子树. 例如以下: class Solution { public:…

37. leetcode 108. Convert Sorted Array to Binary Search Tree

108. Convert Sorted Array to Binary Search Tree 思路:利用一个有序数组构建一个平衡二叉排序树.直接递归构建,取中间的元素为根节点,然后分别构建左子树和右子树.…

[LeetCode] 108. Convert Sorted Array to Binary Search Tree ☆(升序数组转换成一个平衡二叉树)

108. Convert Sorted Array to Binary Search Tree 描述 Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the…

LeetCode 108. Convert Sorted Array to Binary Search Tree （将有序数组转换成BST）

108. Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the tw…

leetcode 108. Convert Sorted Array to Binary Search Tree 、109. Convert Sorted List to Binary Search Tree

108. Convert Sorted Array to Binary Search Tree 这个题使用二分查找,主要要注意边界条件. 如果left > right,就返回NULL.每次更新的时候是mid-1,mid+1. 自己推一下基本就可以验证了. class Solution { public: TreeNode* sortedArrayToBST(vector<int>& nums) { ,nums.size() - ); } TreeNode* ToBST(vecto…

LeetCode 108. Convert Sorted Array to Binary Search Tree （有序数组转化为二叉搜索树）

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 题目标签:Tree 这道题目给了我们一个有序数组,从小到大.让我们把这个数组转化为height balanced BST. 首先来看一下什么是binary search tree: 每一个点的left < 节点 < right, 换一句话说,每一个点的值要大于左边的,小于右边的. 那么什么是heigh…

leetcode 【 Convert Sorted List to Binary Search Tree 】python 实现

题目: Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 代码:oj测试通过 Runtime: 178 ms # Definition for a binary tree node # class TreeNode: # def __init__(self, x): # self.val = x # self.left = No…

[LeetCode 题解]:Convert Sorted List to Binary Search Tree

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 题意:给定一个有序的链表,将其转换成平衡二叉搜索树思路: 二分法要构建一个平衡二叉树,二分法无疑是合适的,至于如何分是的代码简洁,就需要用到递归了. class Solution { public: // find middle element of the list Lis…

leetcode 109 Convert Sorted List to Binary Search Tree ----- java

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 和上一题类似,把数组换成链表,所以可以两种做法: 1.把链表换成数组,然后用上一题的方法,这样会比较慢. 2.每次找到中间的点,作为节点,然后递归,其实原理还是二分查找. /** * Definition for singly-linked list. * public…

Java for LeetCode 108 Convert Sorted Array to Binary Search Tree

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 解题思路: 首先要理解,什么叫做height balanced BST Java for LeetCode 110 Balanced Binary Tree,然后就十分容易了,JAVA实现如下: public TreeNode sortedArrayToBST(int[] nums) { return…

【leetcode】Convert Sorted Array to Binary Search Tree (easy)

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 有序数组变二叉平衡搜索树,不难,递归就行.每次先序建立根节点(取最中间的数),然后用子区间划分左右子树. 一次就AC了注意:new 结构体的时候对于 struct TreeNode { int val; TreeNode *left; TreeNode *right; TreeNode(int x)…

leetcode 108 Convert Sorted Array to Binary Search Tree ----- java

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 给一个排好序的数组,然后求搜索二叉树其实就是二分法,不难. /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNo…

LeetCode 108: Convert Sorted Array to Binary Search Tree DFS求解

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 解题思路: 1. 找到数组的中间节点将其置为根节点 2. 左边的即为左子树 3. 右边的即为右子树 4. 递归求解 /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * Tr…

【leetcode】Convert Sorted List to Binary Search Tree （middle）

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 思路:题目看上去好像很难,但实际上很简单,递归做就行,每次找到左右子树对应的子链表就行.一次AC. class Solution { public: TreeNode *sortedListToBST(ListNode *head) { if(head == NULL) retu…

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