无向连通图,输出每个顶点的度并判断Eulerian.Semi-Eulerian和Non-Eulerian这3种情况,我们直接记录每个点所连接的点,这样直接得到它的度,然后利用深度优先和visit数组来判断图是否连通,不连通直接是Non-Eulerian情况,连通的话再判断顶点的度是否都是偶数,是的话就是Eulerian情况,不是的话再判断它奇数度的个数是否为2个,也就是偶数比总顶点数少2个,是的话就是就是Semi-Eulerian情况了. #include<bits/stdc++.h> usi…

1126 Eulerian Path (25 分) In graph theory, an Eulerian path is a path in a graph which visits every edge exactly once. Similarly, an Eulerian circuit is an Eulerian path which starts and ends on the same vertex. They were first discussed by Leonhard…

1126. Eulerian Path (25) 时间限制 300 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue In graph theory, an Eulerian path is a path in a graph which visits every edge exactly once. Similarly, an Eulerian circuit is an Eulerian path which starts…

1126 Eulerian Path (25 分) In graph theory, an Eulerian path is a path in a graph which visits every edge exactly once. Similarly, an Eulerian circuit is an Eulerian path which starts and ends on the same vertex. They were first discussed by Leonhard…

我是先在CSDN上发布的这篇文章:https://blog.csdn.net/weixin_44385565/article/details/89155050 1126 Eulerian Path (欧拉图的判断) In graph theory, an Eulerian path is a path in a graph which visits every edge exactly once. Similarly, an Eulerian circuit is an Eulerian pat…

https://pintia.cn/problem-sets/994805342720868352/problems/994805349851185152 In graph theory, an Eulerian path is a path in a graph which visits every edge exactly once. Similarly, an Eulerian circuit is an Eulerian path which starts and ends on the…

In graph theory, an Eulerian path is a path in a graph which visits every edge exactly once. Similarly, an Eulerian circuit is an Eulerian path which starts and ends on the same vertex. They were first discussed by Leonhard Euler while solving the fa…

In graph theory, an Eulerian path is a path in a graph which visits every edge exactly once. Similarly, an Eulerian circuit is an Eulerian path which starts and ends on the same vertex. They were first discussed by Leonhard Euler while solving the fa…

题目已经告诉如何判断欧拉回路了,剩下的有一点要注意,可能图本身并不连通. 所以这里用并查集来判断图的联通性. #include <iostream> #include <cstdio> #include <algorithm> #include <string.h> #include <string> using namespace std; /* 并查集用来判断图的联通性,有一组样例图是不连通的... */ ; ]; struct UF{ in…

题意:若图是连通图,且所有结点的度均为偶数,则称为Eulerian:若有且仅有两个结点的度为奇数,则称为semi-Eulerian.现给出一个图,要我们判断其是否为Eulerian,semi-Eulerian还是not-Eulerian. 思路:在数据输入的时候计算各个节点的度:在输出各个节点的度的同时记录度为奇数的结点个数:最后判断判断图是否连通.这种题不考察什么算法,关键要我们理解题意,往往都是很简单的! 代码: #include <cstdio> #include <cstring…