108. Convert Sorted Array to Binary Search Tree 描述 Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the…
108. Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the tw…
108. Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST. /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *ri…
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more th…
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 题目标签:Tree 这道题目给了我们一个有序数组,从小到大.让我们把这个数组转化为height balanced BST. 首先来看一下什么是binary search tree: 每一个点的left < 节点 < right, 换一句话说,每一个点的值要大于左边的,小于右边的. 那么什么是heigh…
1. 题目 1.1 英文题目 Given an integer array nums where the elements are sorted in ascending order, convert it to a height-balanced binary search tree. A height-balanced binary tree is a binary tree in which the depth of the two subtrees of every node never…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 Java解法 Python解法 日期 题目地址:https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/#/description 题目描述 Given an array where elements are sorted in ascending order,…
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more th…
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more th…
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more th…
一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given an array where elements are sorted in ascending order, convert it to a height balanced BST. (二)解题 题目大意:给定一个排好序的数组,将它转变成一个平衡二叉搜索数 解题思路:平衡二叉搜索树的中序遍历为升序数组…
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 解题思路: 首先要理解,什么叫做height balanced BST Java for LeetCode 110 Balanced Binary Tree,然后就十分容易了,JAVA实现如下: public TreeNode sortedArrayToBST(int[] nums) { return…
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 给一个排好序的数组,然后求搜索二叉树 其实就是二分法,不难. /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNo…
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 把一个有序的数组转换为一颗平衡二叉搜索树.每次找到中间节点作为根节点,根节点左边部分转换为左子树,右边部分转换为右子树.代码如下: /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNo…
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 解题思路: 1. 找到数组的中间节点将其置为根节点 2. 左边的即为左子树 3. 右边的即为右子树 4. 递归求解 /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * Tr…
Problem: Given an array where elements are sorted in ascending order, convert it to a height balanced BST. Solution: 复习一下BST的基本性质:简而言之,对于BST中任意结点x,若其有左右结点 l 或 r ,需满足 l.key ≤ x.key ≤ r.key BST的性能(基本操作耗时)与树高成正比,可改进为较为高效的平衡二叉树,即保持整棵树左右均匀,任意左右子树高度差不大于1 如…
原题地址 对于已排序数组,二分法递归构造BST 代码: TreeNode *buildBST(vector<int> &num, int i, int j) { if (i > j) return NULL; ; TreeNode *node = new TreeNode(num[m]); node->left = buildBST(num, i, m - ); node->right = buildBST(num, m + , j); return node; }…
题目: Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 题目只有一句话:把一个按升序排列的数组,装换成一个平衡二叉树. 代码: 很久没研究数据结构了,先百度一下平衡二叉树的概念,总结如下: 若任意节点的左子树不空,则左子树上所有结点的值均小于它的根结点的值: 若任意节点的右子树不空,则右子树上所有结点的值均大于它的根结点的值: 它是一棵空树或它的左右…
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more th…
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 思路:使用二分法,将list的中间节点作为根节点,然后分别处理list左半边及右半边,以此递归. struct TreeNode { int val; TreeNode *left; TreeNode *right; TreeNode(int x) : val(x), left(NULL), right…
108. Convert Sorted Array to Binary Search Tree Easy Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of t…
108. Convert Sorted Array to Binary Search Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two sub…
Problem Link: http://oj.leetcode.com/problems/convert-sorted-array-to-binary-search-tree/ Same idea to Convert Sorted Array to Binary Search Tree, but we use a recursive function to construct the binary search tree. # Definition for a binary tree nod…
LeetCode:Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST 分析:找到数组的中间数据作为根节点,小于中间数据的数组来构造作为左子树,大于中间数据的数组来构造右子树,递归解法如下 /** * Definition for binary tree * struct…
Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 很简单的二分法,只要给出Array的开始和结束下标作为参数传入即可. public TreeNode sortedArrayToBST(int[] num) { return constructBST(num,0,nu…
