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InputThe rst line of the input le contains an integer K | determining the number of datasets. Next linescontain the area descriptions. One description is dened in the following way: The rst line containstwo integers-area length M ≤ 1000 and width N ≤…
题目:给你一个n*n的01矩阵,求里面最大的1组成的矩形的米娜及. 分析:dp.单调队列.UVa 1330同题,仅仅是输入格式变了. 我们将问题分解成最大矩形.即求解以k行为底边的图形中的最大矩形.然后合并.求最大的矩形.                        预处理: 求出以每行为底边的每一列从底边開始向上的最大连续1的高度MaxH. O(N^2) : dp:对于每一层底边.我们利用单调队列求解出本行的最大矩形. O(N). 关于单调队列的求解分析,可參照zoj1985的题解: 整体时…
题目 https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=1030 题意 矩阵,有障碍和普通地面两种子元素,求普通地面连成的子矩阵面积最大值 * 3 思路 如刘书 对于子矩阵长方形来说,其底边上必然有一点,该点向上可以延伸的距离就是子矩阵的长,枚举这一点,设为(i,j).(i,j)不是障碍是普通地面. 令up[i][j]为其向上能…
UVA - 1025 A Spy in the Metro Secret agent Maria was sent to Algorithms City to carry out an especially dangerous mission. After several thrilling events we find her in the first station of Algorithms City Metro, examining the time table. The Algorit…
问题来源:刘汝佳<算法竞赛入门经典--训练指南> P70 例题30: 问题描述:有给你一个n个点m条边(m<n<=1000)的无向无环图,在尽量少的节点上放灯,使得所有边都被照亮,每盏灯将照亮以它为一个端点的所有边.在灯的总数最小的前提下,被两盏灯同时照亮的边数尽量大. 问题分析:1.题中的图,是由多颗树构成的森林,对每颗树用相同的方法即可.  2.本题优化目标:放置的街灯数a应尽量少,在a尽量少的情况下,被两盏灯同时照亮的边数b尽量大(即只被一盏灯照亮的边数c尽量小(b+c=m)…
https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=4829 Patricia is an excellent software developer, but, as every brilliant person, she has some strange quirks.One of those is that everything she d…
 Always on the run Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit Status Practice UVA 590 Appoint description:  System Crawler  (2015-08-26) Description   Screeching tires. Searching lights. Wailing sirens. Police cars…
Strategic game Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit Status Practice UVA 1292 Bob enjoys playing computer games, especially strategic games, but sometimes he cannot find the solution fast enough and then he is…
UVA 11389 Time Limit:1000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Description II U C   ONLINE   C ON TEST   2 008 The Bus Driver Problem Input: standard input Output: standard output In a city there are n bus drivers. Also there are n …
这道题要求我们求出图中的给定的两个节点(一个起点一个终点,但这是无向图)之间所有“路径中最大权值”的最小值,这无疑是动态规划. 我开始时想到根据起点和终点用动态规划直接求结果,但最终由于题中S过大,会超时. 超时的代码如下: #include <iostream> #include <cstdio> #include <cstring> #include <cmath> #include <cstdlib> #include <string…
uva 10192 Vacation The Problem You are planning to take some rest and to go out on vacation, but you really don't know which cities you should visit. So, you ask your parents for help. Your mother says "My son, you MUST visit Paris, Madrid, Lisboa an…
题目链接:uva 11529 - Strange Tax Calculation 题目大意:给出若干个点,保证随意三点不共线.随意选三个点作为三角行,其它点若又在该三角形内,则算是该三角形内部的点.问全部情况的三角形平均每一个三角形有多少个内部点. 解题思路:三角形的总数非常easy求C(3n),如今就是要求各个三角形内部点的总数.相同我们能够反过来,求每一个点在多少个三角形的内部. 然后我们确定一个点,求该点在多少个三角的内部.剩余n-1个点.能够组成C(3n−1])个三角形,所以仅仅要求出该…
Problem    UVA - 11374 - Airport Express Time Limit: 1000 mSec Problem Description In a small city called Iokh, a train service, Airport-Express, takes residents to the airport more quickly than other transports. There are two types of trains in Airp…
UVA 10480 Sabotage (网络流,最大流,最小割) Description The regime of a small but wealthy dictatorship has been abruptly overthrown by an unexpected rebel-lion. Because of the enormous disturbances this is causing in world economy, an imperialist military super…
A Spy in the Metro Time Limit: 3000MS     64bit IO Format: %lld & %llu Submit Status uDebug Secret agent Maria was sent to Algorithms City to carry out an especially dangerous mission. After several thrilling events we find her in the first station o…
UVA - 11374 Airport Express Time Limit:1000MS   Memory Limit:Unknown   64bit IO Format:%lld & %llu [Submit]  [Go Back]  [id=22966" style="color:rgb(106,57,6); text-decoration:none">Status] Description ProblemD: Airport Express In a s…
http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=2369 Description Problem D: Airport Express In a small city called Iokh, a train service, Airport-Express, takes residents to the airport more quick…
2001: [Hnoi2010]City 城市建设 Time Limit: 20 Sec  Memory Limit: 162 MBSubmit: 1132  Solved: 555[Submit][Status][Discuss] Description PS国是一个拥有诸多城市的大国,国王Louis为城市的交通建设可谓绞尽脑汁.Louis可以在某些城市之间修建道路,在不同的城市之间修建道路需要不同的花费.Louis希望建造最少的道路使得国内所有的城市连通.但是由于某些因素,城市之间修建道路需…
原文 Some fresh air After your time underground,you can return to ground level or maybe even a little higher at Kosciuszko Mound. The 34-meter hill is a memorial for a Polish military hero but also offers a panoramic view of surrounding city from top.…
原文 History lives on in this distinguished Polish city Though it may be ancient. KraKow, Poland, is alive and well as it celebrates and commemorates its meaningful history. Looking up When scaning the skies of Krakow,most agree that Wawel Castle cast…
时间限制:10000ms 单点时限:1000ms 内存限制:256MB 描述 Little Hi gets lost in the city. He does not know where he is. He does not know which direction is north. Fortunately, Little Hi has a map of the city. The map can be considered as a grid of N*M blocks. Each blo…
Here is a brief outline of the steps needed to install GeoIP Legacy City on Linux/Unix. The installation on Windows is similar, just replace the tar command with WinZip or a similar ZIP program. Step 1 – Download database For GeoIP clients, go to the…
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UVA - 10564 Paths through the Hourglass 题意: 要求从第一层走到最下面一层,只能往左下或右下走 问有多少条路径之和刚好等于S? 如果有的话,输出字典序最小的路径. f[i][j][k]从下往上到第i层第j个和为k的方案数 上下转移不一样,分开处理 没必要判断走出沙漏 打印方案倒着找下去行了,尽量往左走   沙茶的忘注释掉文件WA好多次   #include <iostream> #include <cstdio> #include <a…
UVA - 11404 Palindromic Subsequence 题意:一个字符串,删去0个或多个字符,输出字典序最小且最长的回文字符串 不要求路径区间DP都可以做 然而要字典序最小 倒过来求LCS,转移同时维护f[i][j].s为当前状态字典序最小最优解 f[n][n].s的前半部分一定是回文串的前半部分(想想就行了) 当s的长度为奇时要多输出一个(因为这样长度+1,并且字典序保证最小(如axyzb  bzyxa,就是axb|||不全是回文串的原因是后半部分的字典序回文串可能不是最小,多…
POJ3869 Headshot 题意:给出左轮手枪的子弹序列,打了一枪没子弹,要使下一枪也没子弹概率最大应该rotate还是shoot 条件概率,|00|/(|00|+|01|)和|0|/n谁大的问题 |00|+|01|=|0| 注意序列是环形 // // main.cpp // poj3869 // // Created by Candy on 25/10/2016. // Copyright © 2016 Candy. All rights reserved. // #include <i…
UVA - 11538 Chess Queen 题意:n*m放置两个互相攻击的后的方案数 分开讨论行 列 两条对角线 一个求和式 可以化简后计算 // // main.cpp // uva11538 // // Created by Candy on 24/10/2016. // Copyright © 2016 Candy. All rights reserved. // #include <iostream> #include <cstdio> #include <cst…
UVA - 11388 GCD LCM 题意:输入g和l,找到a和b,gcd(a,b)=g,lacm(a,b)=l,a<b且a最小 g不能整除l时无解,否则一定g,l最小 #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> using namespace std; typedef long long ll…
UVA - 1625 Color Length   白书 很明显f[i][j]表示第一个取到i第二个取到j的代价 问题在于代价的计算,并不知道每种颜色的开始和结束   和模拟赛那道环形DP很想,计算这次转移会给其他的元素带来的代价,也就是转移前已经出现但还没结束的元素都会代价+1   预处理每种颜色在两个序列中出现的位置bg[i][0/1]和ed[i][0/1], 计算f[i][j]时同时计算w[i][j]为(i,j)这个状态已经出现还没结束的个数 注意bg要先初始化为INF,计算w: if(b…
UVA - 10375 Choose and divide Choose and divide Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 4053   Accepted: 1318 Description The binomial coefficient C(m,n) is defined as m! C(m,n) = -------- n!(m-n)! Given four natural numbers p, q…