Rich Game Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 72    Accepted Submission(s): 34 Problem Description One day, God Sheep would like to play badminton but he can’t find an opponent. So h…

Too Rich Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 245    Accepted Submission(s): 76 Problem Description You are a rich person, and you think your wallet is too heavy and full now. So yo…

题目链接 Problem Description You are a rich person, and you think your wallet is too heavy and full now. So you want to give me some money by buying a lovely pusheen sticker which costs pdollars from me. To make your wallet lighter, you decide to pay exa…

题目连接 Problem Description They say that in Phrygia, the streets are paved with gold. You're currently on vacation in Phrygia, and to your astonishment you discover that this is to be taken literally: small heaps of gold are distributed throughout the…

Too Rich Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 1850    Accepted Submission(s): 480 Problem Description You are a rich person, and you think your wallet is too heavy and full now. So…

Too Rich Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 395    Accepted Submission(s): 118 Problem DescriptionYou are a rich person, and you think your wallet is too heavy and full now. So yo…

单纯dp 水一 处理时间点,第一行和第一列特殊处理: 其余的w[i][j]=show(w[i-1][j-1],w[i-1][j],w[i][j-1]); <span style="font-size:24px;"><span style="font-size:24px;">#include<stdio.h> #include<string.h> #include<algorithm> #include<…

http://www.cnblogs.com/AOQNRMGYXLMV/p/4934747.html #include<iostream> #include<cstdio> #include<algorithm> using namespace std; ; const int inf=0x3f3f3f3f; int a[maxn]; int b[maxn]; ,,,,,,,,,}; int Solve(int t) { ; ;i>=;i--) { ||i==)…

题意: 有\(10\)种面值为\(1, 5, 10, 20, 50, 100, 200, 500, 1000, 2000\)的纸币,现在你要选最多的数量凑成\(p\)块钱. 分析: 同样分析问题的反面:设总金额为\(sum\),我们来求凑成\(sum-p\)所需要的最少的张数.那么剩下的就是凑成\(p\)的最多的张数. 如果没有\(50\)和\(500\)的面值的话,那么后一种面值都是前一种面值的倍数,显然贪心是可以的. 贪心的理由就是完全可以用大面值替换掉对应数量的小面值的钱,这样总钱数不变但…

题目链接 题意 给出p块钱,现在要用十种硬币凑出,每种硬币有c[i]个,问最多能用多少个硬币. 思路 首先确定,对于每个硬币就是能用小的替换就不用大的. 所以,可以先把硬币尽量用小的替换,如果小的不够用,再用大的去替换. 根据这个思路,就可以处理出一个前 i 个硬币总价值的前缀和 pre[],从大的面额到小面额去枚举,当前这种面额的硬币至少需要使用 (sum - pre[i-1]) / val[i] 种,sum代表当前还剩下多少钱要去兑换,这个数要向上取整,然后继续dfs下去就可以了. 还有一种…

题目链接 题意 : 给出一些固定面值的硬币的数量.再给你一个总金额.问你最多能用多少硬币来刚好凑够这个金额.硬币数量和总金额都很大   分析 : 长春赛区的金牌题目 一开始认为除了做类似背包DP那样子的DP外.别无他法 时空限制下是不可能DP的 众所周知背包DP问题贪心是错的 遂认定不是贪心方向 看到题解.真香~ 这种凑硬币问题.如果满足一个条件.那么贪心是正确的 当然和这道题目不一样.可贪心的是要求用最少的硬币凑出总金额 需要满足的条件是.可选择的硬币面额满足大面额是小面额的倍数 如果不满足上…

E - The Boss on Mars Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 4059 Description On Mars, there is a huge company called ACM (A huge Company on Mars), and it’s owned by a younger boss. Due…

Constructing Roads In JGShining's Kingdom Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 23467    Accepted Submission(s): 6710 Problem Description JGShining's kingdom consists of 2n(n is no mo…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=2120 Ice_cream's world I Description ice_cream's world is a rich country, it has many fertile lands. Today, the queen of ice_cream wants award land to diligent ACMers. So there are some watchtowers are s…

An Easy Problem for Elfness Time Limit: 5000/2500 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 1148    Accepted Submission(s): 234 Problem Description Pfctgeorge is totally a tall rich and handsome guy. He plans t…

Too Rich http://acm.hdu.edu.cn/showproblem.php?pid=5527 Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 2032    Accepted Submission(s): 529 Problem Description You are a rich person, and you t…

题目链接: acm.hdu.edu.cn/showproblem.php?pid=1025 Constructing Roads In JGShining's Kingdom Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 28755    Accepted Submission(s): 8149 Problem Description…

http://acm.hdu.edu.cn/showproblem.php?pid=2103 Problem Description As far as we known,there are so many people in this world,expecially in china.But many people like LJ always insist on that more people more power.And he often says he will burn as mu…

HDOJ(HDU).1025 Constructing Roads In JGShining's Kingdom (DP) 点我挑战题目 题目分析 题目大意就是给出两两配对的poor city和rich city,求解最多能修几条不相交的路.此题可以转化为LIS问题.转化过程如下: 数据中有2列,为方便表述,暂且叫做第一列和第二列. 1.若第一列是是递增的(给出的2个样例都是递增的),那么要想尽可能多的做连线,则那么就需要找出第二列中最长的递增子序列,若出现非递增的序列,那么连线后一定会相交.…

题目HDU 2103:http://acm.hdu.edu.cn/showproblem.php?pid=2103 Problem Description As far as we known,there are so many people in this world,expecially in china.But many people like LJ always insist on that more people more power.And he often says he will…

http://acm.hdu.edu.cn/showproblem.php?pid=1025 Constructing Roads In JGShining's Kingdom Problem Description   JGShining's kingdom consists of 2n(n is no more than 500,000) small cities which are located in two parallel lines.Half of these cities are…

本人蒟蒻,5个小时过了5道,看到好几个大佬AK,%%%%%%% http://acm.hdu.edu.cn/contests/contest_show.php?cid=868 先放大佬的题解(不是我写的..同学给的),能理解多少就靠你们自己了,还是希望大家能从大佬的题解中有所收获 口胡题解: A. Co-Tree:由目标函数提到的两两距离和,可想到,在树上找个点,使得它到其它点距离和最小. B. Math:考虑每秒开始时 “avin 拿着 Robot 在 i 点” 的状态 到 “Avin 拿着…

软件开发是现时很火的职业.据美国劳动局发布的一项统计数据显示,从2014年至2024年,美国就业市场对开发人员的需求量将增长17%,而这个增长率比起所有职业的平均需求量高出了7%.很多人年轻人会选择编程作为自己职业生涯的起点.如何学好编程?如何成为优秀的程序员?如何规划好程序员这个职业?是许多年轻人关注的问题.在Infoworld最近做的一次调查中,邀请到了JavaScript之父Brendan Eich,Clojure 创建者Rich Hickey,Spring Framework创建者Rod…

Saving HDU Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 7194    Accepted Submission(s): 3345 Problem Description 话说上回讲到海东集团面临内外交困,公司的元老也只剩下XHD夫妇二人了.显然,作为多年拼搏的商人,XHD不会坐以待毙的.  一天,当他正在苦思冥想解困良策的…

http://acm.hdu.edu.cn/showproblem.php?pid=3037 Lucas定理模板. 现在才写,noip滚粗前兆QAQ #include<cstdio> #include<cstring> #include<algorithm> using namespace std; typedef long long ll; int jc[100003]; int p; int ipow(int x, int b) { ll t = 1, w = x;…

http://acm.hdu.edu.cn/showproblem.php?pid=4859 题目大意: 在一个矩形周围都是海,这个矩形中有陆地,深海和浅海.浅海是可以填成陆地的. 求最多有多少条方格线满足两侧分别是海洋和陆地 这道题很神 首先考虑一下,什么情况下能够对答案做出贡献 就是相邻的两块不一样的时候 这样我们可以建立最小割模型,可是都说是最小割了 无法求出最大的不相同的东西 所以我们考虑转化,用总的配对数目 - 最小的相同的对数 至于最小的相同的对数怎么算呢? 我们考虑这样的构造方法:…

Special equations Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 4569 Description Let f(x) = a nx n +...+ a 1x +a 0, in which a i (0 <= i <= n) are all known integers. We call f(x) 0 (mod…

The kth great number Time Limit:1000MS     Memory Limit:65768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 4006 Description Xiao Ming and Xiao Bao are playing a simple Numbers game. In a round Xiao Ming can choose to write down a nu…

How many integers can you find Time Limit:5000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1796 Description   Now you get a number N, and a M-integers set, you should find out how many integers which are sm…

(转)http://blog.csdn.net/u013081425/article/details/39240021 http://acm.hdu.edu.cn/showproblem.php?pid=4418 读了一遍题后大体明白意思,但有些细节不太确定.就是当它处在i点处,它有1~m步可以走,但他走的方向不确定呢.后来想想这个方向是确定的,就是他走到i点的方向,它会继续朝着这个方向走,直到转向回头. 首先要解决的一个问题是处在i点处,它下一步该到哪个点.为了解决方向不确定的问题,将n个点转…