主题链接:http://acm.hdu.edu.cn/showproblem.php? pid=5095 Problem Description SVM(Support Vector Machine)is an important classification tool, which has a wide range of applications in cluster analysis, community division and so on. SVM The kernel function…

比较坑的水题,首项前面的符号,-1,+1,只有数字项的时候要输出0. 感受一下这些数据 160 0 0 0 0 0 0 0 0 -10 0 0 0 0 0 0 0 0 10 0 0 0 0 0 0 0 0 01 0 0 0 0 0 0 0 0 0-1 0 0 0 0 0 0 0 0 0-1 -1 -1 -41 -1 -1 -1 -1 -1 -1-1 5 -2 0 0 0 0 0 0 01 1 1 1 1 1 1 1 1 1-1 -1 -1 -1 -1 -1 -1 -1 -1 -10 0 0 0…

题意: INPUT: The input of the first line is an integer T, which is the number of test data (T<120). Then T data follows. For each data, there are 10 integer numbers on one line, which are the coefficients and constant a, b, c, d, e, f, g, h, i, j of th…

题目传送门 /* 题意:表达式转换 模拟:题目不难,也好理解题意,就是有坑!具体的看测试样例... */ #include <cstdio> #include <algorithm> #include <iostream> #include <cstring> #include <cmath> #include <string> #include <vector> #include <queue> #inclu…

Description SVM(Support Vector Machine)is an important classification tool, which has a wide range of applications in cluster analysis, community division and so on. SVM The kernel functions used in SVM have many forms. Here we only discuss the funct…

Linearization of the kernel functions in SVM Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 2232    Accepted Submission(s): 598 Problem Description SVM(Support Vector Machine)is an important c…

In recent years, Kernel methods have received major attention, particularly due to the increased popularity of the Support Vector Machines. Kernel functions can be used in many applications as they provide a simple bridge from linearity to non-linear…

==================================================================== This article came from here. Thanks for zhizhihu. ==================================================================== Kernel Functions Below is a list of some kernel functions avai…

Kernel Functions-Introduction to SVM Kernel & Examples - DataFlairhttps://data-flair.training/blogs/svm-kernel-functions/…

http://acm.hdu.edu.cn/showproblem.php?pid=5095 就是把ax^2 + by^2 + cy^2 + dxy + eyz + fzx + gx + hy + iz + j转换成ap + bq + cr + du + ev + fw + gx + hy + iz + j 注意的地方就是开头不要有+,系数为0不输出,系数为1的话不能输出系数除非指数为0等等 #include <cstdio> #include <cstdlib> #include…

huffman coding, greedy algorithm. std::priority_queue, std::partition, when i use the three commented lines, excution time increase to 15ms from 0ms, due to worse locality? thanks to http://acm.hdu.edu.cn/discuss/problem/post/reply.php?action=support…

关键词:netem(Network Emulator).tc(Traffic Control). 大部分局域网环境良好,但是产品实际网络环境可能千差万别,为了对产品进行各种情况测试就需要模拟网络环境. Linux内核network模块提供了NetworkEmulator功能,结合iproute2的tc功能可以模拟各种网络环境. 还有一点好处就是可以固定特殊网络环境,进行bug复现. 1. 环境准备 要模拟网络环境,首先需要Kernel支持netem,并且需要tc工具. 使能netem功能,在ma…

Just a Numble Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2107    Accepted Submission(s): 987 Problem Description Now give you two integers n m, you just tell me the m-th number after radix…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4772 题面: Zhuge Liang's Password Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1404    Accepted Submission(s): 926 Problem Description In the anc…

题目链接:pid=5402">http://acm.hdu.edu.cn/showproblem.php?pid=5402 题意:给出一个n×m的矩阵,位置(i.j)有一个非负权值. 每一个点仅仅能经过一次.求从(1.1)到(n.m)权值总和最大的和.还需输出路径. 思路:由于走的点越多越好,所以得到规律,当n,m随意一个为奇数时.均能够走全然部点. 当n,m全为偶数时,当点(i.j)的i和j不同奇偶时,则除了(i,j)这个点均能够走完剩下的全部点. 剩下模拟就可以. n,m当中一个为奇数…

题目地址:pid=5373">HDU 5373 题意:给你一个数n和操作次数t,每次操作将n的各位数之和求出来放在n的末尾形成新的n,问t次操作后得到的n能否够被11整除. 思路:就是简单的模拟一下乱搞.额,对于%11有一个性质,当一个数的奇数位之和与偶数位之和的差的绝对值能被11整除,那么该数就能够被11整除. #include <stdio.h> #include <math.h> #include <string.h> #include <s…

以为是贪心,结果不是,2333 贪心最后对自己绝对有利的情况 点我 #include<cstdio> #include<iostream> #include<algorithm> #include<cstring> #include<cmath> #include<queue> #include<map> using namespace std; #define MOD 1000000007 const int INF=0…

a problem where OO seems more natural to me, implementing a utility class not instantiable. how to prevent instantiation, thanks to http://stackoverflow.com/questions/10558393/prevent-instantiation-of-an-object-outside-its-factory-method/10558404#105…

题目 大意: 求二进制的a加到b的进位数. 思路: 列出前几个2进制,找规律模拟. #include <stdio.h> #include <iostream> #include <algorithm> #include <string.h> #include <math.h> #include <stack> #include <vector> using namespace std; int main() { int…

题目链接 用p[a]保存的是输入的a在第p[a]个,  然后根据差值查找. #include<stdio.h> #include<string.h> int main() { ]; scanf("%d",&t); while(t--) { flag=; scanf("%d",&n); ;i<n;i++) { scanf("%d",&a); p[a]=i; } m=n/; ;j<m;j++…

不容易系列之二 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 19635    Accepted Submission(s): 15810 Problem Description 你活的不容易,我活的不容易,他活的也不容易.不过,如果你看了下面的故事,就会知道,有位老汉比你还不容易. 重庆市郊黄泥板村的徐老汉(大号徐东海,简称XDH)…

Problem Description It's yet another festival season in Gensokyo. Little girl Alice planned to pick mushrooms in five mountains. She brought five bags with her and used different bags to collect mushrooms from different mountains. Each bag has a capa…

Description 上次Gardon的迷宫城堡小希玩了很久(见Problem B),现在她也想设计一个迷宫让Gardon来走.但是她设计迷宫的思路不一样,首先她认为所有的通道都应该是双向连通的,就是说如果有一个通道连通了房间A和B,那么既可以通过它从房间A走到房间B,也可以通过它从房间B走到房间A,为了提高难度,小希希望任意两个房间有且仅有一条路径可以相通(除非走了回头路).小希现在把她的设计图给你,让你帮忙判断她的设计图是否符合她的设计思路.比如下面的例子,前两个是符合条件的,但是最后一个…

给出一个序列(长度>=2),问去掉一个元素后是否能成为单调不降序列或单调不增序列. 对任一序列,先假设其可改造为单调不降序列,若成立则输出YES,不成立再假设其可改造为单调不增序列,若成立则输出YES,不成立则输出NO. 由于持平不影响整体单调性,为了直观,我在以下把“不降”称为“递增/升序”,把“不增”称为“递减/降序”. 递增和递减是对称的,这里先考虑递增,递减改个符号和最值就好. 我们把为维护单调性而去掉的那个点称为“坏点”.由题目的要求,“可改造”可等价于“只存在一个坏点”. 对于“坏点…

Problem Description 数论中有许多猜想尚未解决,其中有一个被称为“角谷猜想”的问题,该问题在五.六十年代的美国多个著名高校中曾风行一时,这个问题是这样描述的:任何一个大于一的自然数,如果是奇数,则乘以三再加一:如果是偶数,则除以二:得出的结果继续按照前面的规则进行运算,最后必定得到一.现在请你编写一个程序验证他的正确性.   Input 本题有多个测试数据组,第一行为测试数据组数N,接着是N行的正整数.   Output 输出验证“角谷猜想”过程中的奇数,最后得到的1不用输出:…

Problem Description There was no donkey ,) , the down-right cell ,N-) and the cell below the up-left cell ,)..... A × grid is shown below: The donkey lived happily until it saw a tiger far away. The donkey had never seen a tiger ,and the tiger had ne…

这是一道5Y的题目 有坑的地方我已在代码中注释好了 QAQ Ps:模拟题还是练的太少了,速度不够快诶 //#pragma comment(linker, "/STACK:16777216") //for c++ Compiler #include <stdio.h> #include <iostream> #include <climits> #include <cstring> #include <cmath> #inclu…

题意: 给定一棵树,每个节点代表一个员工,节点编号小的级别就小,那么点1就是boss了.接下来给出对m个点的限制,有3种符号分别是op=“大于/小于/等于”,表示以第i个点为根的子树所有人的工资之和 大于/小于/等于 x,要求判断m个限制是否冲突了.注意每个员工的工资下限是1,而无上限.ps:可能出现对同个点多个限制,注意取交集. 思路: 很水的题嘛,想复杂了.注意限制是针对整棵子树的!所以我们只需要算出这棵子树的范围,再判断是否和所给的限制有冲突,如果没有冲突的话还得取“所给限制”与“计算出的…

题目 这是传说中的深搜吗....不确定,,,,貌似更加像是模拟,,,, //我要做深搜题目拉 //实际上还是模拟 #include<iostream> #include<string> #include<stdio.h> #include<string.h> #include<math.h> #include<algorithm> using namespace std; int ans; ]; __int64 n; ]; int l…

转自 http://www.zhizhihu.com/html/y2010/2292.html Kernel Functions Below is a list of some kernel functions available from the existing literature. As was the case with previous articles, every LaTeX notation for the formulas below are readily availabl…