/** 题目:Time Limit Exceeded 链接:https://oj.ejq.me/problem/28 题意:求逆序对数. 思路:树状数组求逆序对数.维护前面有多少个<=当前数的数的个数. */ #include<bits/stdc++.h> typedef long long ll; using namespace std; ; ; ll c[maxn]; int flag[maxn]; int n; int a[maxn]; int lowbit(int t) { re…

Ultra-QuickSort 题目链接:http://poj.org/problem?id=2299 Time Limit: 7000MS   Memory Limit: 65536K Total Submissions: 51641   Accepted: 18948 Description In this problem, you have to analyze a particular sorting algorithm. The algorithm processes a sequen…

#返回上一级 @Author: 张海拔 @Update: 2014-01-14 @Link: http://www.cnblogs.com/zhanghaiba/p/3520089.html /* *Author: ZhangHaiba *Date: 2014-1-15 *File: inverse_number.c * *this demo shows two method solving inverse number problem */ #include <stdio.h> #defin…

Ultra-QuickSort Time Limit: 7000MS   Memory Limit: 65536K Total Submissions: 46995   Accepted: 17168 Description In this problem, you have to analyze a particular sorting algorithm. The algorithm processes a sequence of n distinct integers by swappin…

Inversion                                                                             Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Problem Description bobo has a sequence a1,a2,-,an. He is allowed to swap two …

Swaps and Inversions Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2787    Accepted Submission(s): 1071 Problem Description Long long ago, there was an integer sequence a.Tonyfang think this s…

Time Limit: 7000MS   Memory Limit: 65536K Total Submissions: 34283   Accepted: 12295 Description In this problem, you have to analyze a particular sorting algorithm. The algorithm processes a sequence of n distinct integers by swapping two adjacent s…

题目链接 ac代码 #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<bitset> #include<cassert> #include<cctype> #include<cmath> #include<cstdlib> #include<ctime> #include&…

题意:废话了一大堆就是要你去求一个序列冒泡排序所需的交换的次数. 思路:实际上是要你去求一个序列的逆序队数 看案例: 9 1 0 5 4 9后面比它小的的数有4个 1后面有1个 0后面没有 5后面1个 4后面没有 所以结果为4+1+0+1+0=6 所以逆序对的定义假设不清楚能够自己总结了 这道题说白了就是要你用归并排序求逆序对数. 以下是搜到某牛给的逆序对数的方法: 如果回溯到某一步,后面的两部分已经排好序(就是说当前须要归并的两个部分都是分别有序的).如果这两个序列为 序列a1:2 3 5 9…

题目:http://acm.hdu.edu.cn/showproblem.php?pid=2443 这个题目尝试了很多种方法都过不去,上网查了一下网友们的的思路,竟然和逆序对数有关系!! 题目大意: 有n个士兵,他们都有各自的分数,有一项任务需要完成,为了能够确保合作更默契,他们的分数要差不多,所以有一个水平控制即平均数,所选的一组士兵的平均成绩必须大于该平均数. 问一共能选出多少组士兵能够完成该项任务? 思路: 求逆序对数.归并排序可以用来求逆序对数,这个没毛病. 代码如下: #include…