C. Little Girl and Maximum Sum time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard output The little girl loves the problems on array queries very much. One day she came across a rather well-known proble…
题意: 给出n项的数列A[ ], q个询问, 询问 [ l, r ] 之间项的和. 求A的全排列中该和的最大值. 思路: 记录所有询问, 利用差分数列qd[ ], 标记第 i 项被询问的次数( 每次区间增1 ). 最后对qd, A 进行升序排序, 对应项相乘, 求和. 理由是: 越大的数被询问覆盖的次数越多那么总和就越大. 差分数列简单易用. #include <cstdio> #include <cstring> #include <algorithm> using…
B. Maximum Sum of Digits time limit per test 2 seconds memory limit per test 512 megabytes input standard input output standard output You are given a positive integer nn. Let S(x)S(x) be sum of digits in base 10 representation of xx, for example, S(…
Maximum Sum of Digits You are given a positive integer n. Let S(x)S(x) be sum of digits in base 10 representation of xx , for example, S(123)=1+2+3=6S(123)=1+2+3=6 , S(0)=0S(0)=0 . Your task is to find two integers a,ba,b , such that 0≤a,b≤n0≤a,b≤n ,…
[抄题]: In a given array nums of positive integers, find three non-overlapping subarrays with maximum sum. Each subarray will be of size k, and we want to maximize the sum of all 3*k entries. Return the result as a list of indices representing the star…
Maximum sum Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 39599   Accepted: 12370 Description Given a set of n integers: A={a1, a2,..., an}, we define a function d(A) as below: Your task is to calculate d(A). Input The input consists o…
1146. Maximum Sum Time limit: 0.5 secondMemory limit: 64 MB Given a 2-dimensional array of positive and negative integers, find the sub-rectangle with the largest sum. The sum of a rectangle is the sum of all the elements in that rectangle. In this p…
CF 628C 题目大意:给定一个长度为n(n < 10^5)的只含小写字母的字符串,以及一个数d,定义字符的dis--dis(ch1, ch2)为两个字符之差, 两个串的dis为各个位置上字符的dis之和,求和给定的字符串的dis为d的字符串,若含有多个则输出任意一个,不存在输出-1 解题思路:简单贪心,按顺序往后,对每一个字符,将其变为与它dis最大的字符(a或者z),d再减去相应的dis, 一直减到d为0,剩余的字母则不变直接输出.若一直到最后一位d仍然大于0,则说明不存在,输出-1. /…
题目来源:https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=3&page=show_problem&problem=44  Maximum Sum  Background A problem that is simple to solve in one dimension is often much more difficult to solve in more th…
题目传送门 /* 最大子矩阵和:把二维降到一维,即把列压缩:然后看是否满足最大连续子序列: 好像之前做过,没印象了,看来做过的题目要经常看看:) */ #include <cstdio> #include <iostream> #include <cstring> #include <algorithm> using namespace std; ; const int INF = 0x3f3f3f3f; int a[MAXN][MAXN]; int dp[…