题目连接: http://poj.org/problem?id=2387 Description Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the morning milking. Bessie needs her beauty sleep, so she wants to get ba…

题目链接:http://poj.org/problem?id=2387 题意:有n个城市点,m条边,求n到1的最短路径.n<=1000; m<=2000 就是一个标准的最短路模板. #include<iostream> #include<algorithm> #include<cstring> #include<vector> #include<queue> using namespace std; ; const int INF =…

Dijkstra模板题,也可以用Floyd算法. 关于Dijkstra算法有两种写法,只有一点细节不同,思想是一样的. 写法1: #include <iostream> #include <cstdio> #include <cstring> #include <cmath> #include <algorithm> #define Mod 1000000007 using namespace std; #define N 1007 int mp…

POJ 2387 Til the Cows Come Home (图论,最短路径) Description Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the morning milking. Bessie needs her beauty sleep, so she wants to g…

POJ.2387 Til the Cows Come Home (SPFA) 题意分析 首先给出T和N,T代表边的数量,N代表图中点的数量 图中边是双向边,并不清楚是否有重边,我按有重边写的. 直接跑spfa,dij,floyd都可以. 求1到N的最短路. 代码总览 #include <cstdio> #include <cstring> #include <algorithm> #include <queue> #include <stack>…

Til the Cows Come Home 最短路Dijkstra+bellman(普通+优化) 贝西在田里,想在农夫约翰叫醒她早上挤奶之前回到谷仓尽可能多地睡一觉.贝西需要她的美梦,所以她想尽快回来. 农场主约翰的田里有n(2<=n<=1000)个地标,唯一编号为1..n.地标1是谷仓:贝西整天站在其中的苹果树林是地标n.奶牛在田里行走时使用地标间不同长度的T(1<=t<=2000)双向牛道.贝西对自己的导航能力没有信心,所以一旦开始,她总是沿着一条从开始到结束的路线行进. 根…

题目链接:http://poj.org/problem?id=2387 Til the Cows Come Home Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 45414   Accepted: 15405 Description Bessie is out in the field and wants to get back to the barn to get as much sleep as possible…

传送门 Til the Cows Come Home Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 46727   Accepted: 15899 Description Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for…

Til the Cows Come Home Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 33015   Accepted: 11174 Description Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the…

Til the Cows Come Home 题目链接: http://acm.hust.edu.cn/vjudge/contest/66569#problem/A Description Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the morning milking. Bessie…

Til the Cows Come Home Description Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the morning milking. Bessie needs her beauty sleep, so she wants to get back as quickly…

Til the Cows Come Home Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the morning milking. Bessie needs her beauty sleep, so she wants to get back as quickly as possible.…

原题链接:Til the Cows Come Home 题目大意:有  个点,给出从  点到  点的距离并且  和  是互相可以抵达的,问从  到  的最短距离. 题目分析:这是一道典型的最短路径模版题,需要注意的是:使用dijkstra算法求解需要考虑有重复边问题,而使用bellman-ford算法 和 spfa算法 可以忽略这个问题. 代码如下: // Dijkstra #include <iostream> using namespace std; const int INTFY = 1…

AC代码 POJ2387 Til the Cows Come Home Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the morning milking. Bessie needs her beauty sleep, so she wants to get back as quickly…

题目链接:http://poj.org/problem?id=2387 题目大意:起点一定是1,终点给出,然后求出1到所给点的最短路径. 注意的是先输入边,在输入的顶点数,不要弄反哦~~~ #include <iostream> #include <cstdio> using namespace std; ][],Min,node[],vis[],t,q; ; void set() { ; i<=; i++) { node[i]=INF; vis[i]=; ; j<=;…

题目链接:http://poj.org/problem?id=2387 题目大意:给你t条边(无向图),n个顶点,让你求点1到点n的最短距离. 解题思路:裸的dijsktra,注意判重边. 代码: #include<cstdio> #include<cmath> #include<cctype> #include<cstring> #include<iostream> #include<algorithm> #include<v…

传送门:http://poj.org/problem?id=2387 题目大意: 给定无向图,要求输出从点n到点1的最短路径. 注意有重边,要取最小的. 水题..对于无向图,从1到n和n到1是一样的. 直接Dijkstra即可 #include<cstdio> #include<cstring> const int MAXN=1000+10; const int INF=999999; int map[MAXN][MAXN]; int dis[MAXN]; int main() {…

Description Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the morning milking. Bessie needs her beauty sleep, so she wants to get back as quickly as possible. Farmer Joh…

Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the morning milking. Bessie needs her beauty sleep, so she wants to get back as quickly as possible. Farmer John's field ha…

Time Limit: 1000MSMemory Limit: 65536K Total Submissions: 59755Accepted: 20336 Description Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the morning milking. Bessie need…

Description Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the morning milking. Bessie needs her beauty sleep, so she wants to get back as quickly as possible. Farmer Joh…

Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the morning milking. Bessie needs her beauty sleep, so she wants to get back as quickly as possible. Farmer John's field ha…

题目 #define _CRT_SECURE_NO_WARNINGS #include<string.h> #include<stdio.h> #include<math.h> ; #define typec int const typec INF=0x3f3f3f3f;//防止后面溢出,这个不能太大 bool vis[MAXN]; int pre[MAXN]; typec cost[MAXN][MAXN]; typec lowcost[MAXN]; void Dijk…

求1到N的最短路 注意有重边 跑一遍dijkstra就行 /* *********************************************** Author :Sun Yuefeng Created Time :2016/10/22 14:18:06 File Name :A.cpp ************************************************ */ #include<cstdio> #include<iostream> #inc…

(￣▽￣)" //dijkstra算法: //这题建邻接矩阵的时候有坑(先读入边后读入点),还有重边: #include<iostream> #include<cstdio> using namespace std; const int INF=10e7; ; int k,minn; int cost[MAXN][MAXN]; int lowcost[MAXN]; bool vis[MAXN]; void dij(int n,int start) { ;i<=n;i…

题目:从节点N到节点1的求最短路径. 分析:这道题陷阱比较多,首先是输入的数据,第一个是表示路径条数,第二个是表示节点数量,在 这里WA了四次.再有就是多重边,要取最小值.最后就是路径的长度的最大值不是100,而是100001.用Dijkstra求最短路径,感觉 Dijkstra和Prim很像,都是从结点中找到路径最小的一条,然后再做某种更新.Dijkstra是看看源节点通过当前节点能否缩短从源头到其他节 点的路径,而Prim则是通过加入当前节点到生成树,然后更新生成树中的路径数量,再从中找到最…

从点N到1的最短路 *记得无向图两个方向都要建边就好了…… 以及多组数据= = #include <iostream> #include <cstdio> #include <cstring> #include <queue> using namespace std; #define SZ 4005 #define INF 1e9+10 ; struct edge { int t,d; }l[SZ]; void build(int f,int t,int d…

Til the Cows Come Home 大奶牛很热爱加班,他和朋友在凌晨一点吃完海底捞后又一个人回公司加班,为了多加班他希望可以找最短的距离回到公司.深圳市里有N个(2 <= N <= 1000)个公交站,编号分别为1..N.深圳是大城市,公交车整天跑跑跑.公交站1是大奶牛的位置,公司所在的位置是N.所有公交站中共有T (1 <= T <= 2000)条双向通道.大奶牛对自己的导航能力不太自信,所以一旦开始,他总是沿着一条路线走到底.大奶牛为了锻炼未来的ACMer,决定让你帮…

题目链接:http://poj.org/problem?id=2387 题意:求从1到n的最短路 题解:板子题.spfa. 代码: #include<iostream> #include<stack> #include<vector> #include<queue> #include<algorithm> using namespace std; ; vector< pair<int,int> > e[maxn]; int…

题目链接: http://poj.org/problem?id=2387 Description Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the morning milking. Bessie needs her beauty sleep, so she wants to get ba…