大菲波数 Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 16257    Accepted Submission(s): 5403 Problem Description Fibonacci数列,定义如下:f(1)=f(2)=1f(n)=f(n-1)+f(n-2) n>=3.计算第n项Fibonacci数值.   Input 输入第一行…

A + B Problem II Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 230395    Accepted Submission(s): 44208 Problem Description I have a very simple problem for you. Given two integers A and B, you…

数字的反转: 就是将数字倒着存下来而已.(*^__^*) 嘻嘻…… 大致思路:将数字一位一位取出来,存在一个数组里面,然后再将其变成数字,输出. 详见代码. while (a) //将每位数字取出来,取完为止 { num1[i]=a%; //将每一个各位取出存在数组里面,实现了将数字反转 i++; //数组的变化 a/=; } 趁热打铁 例题:hdu 4554 叛逆的小明 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4554 叛逆的小明 Time…

原题代号:HDU 1002 原题链接:http://acm.hdu.edu.cn/showproblem.php?pid=1002 原题描述: Problem Description I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.   Input The first line of the input contains an i…

http://acm.hdu.edu.cn/showproblem.php?pid=1002 PE   由于最后一个CASE不须要输出空行 import java.math.BigInteger; import java.util.Scanner; public class Main { public static void main(String args[]){ Scanner in = new Scanner(System.in); int ncase; ncase = in.nextIn…

package Main; //import java.io.InputStream; import java.math.BigDecimal; import java.util.Scanner; public class Main { public static void main(String[] args) { int _case; BigDecimal a,b; a=new BigDecimal("0"); b=new BigDecimal("0"); Sc…

A + B Problem II Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 347161    Accepted Submission(s): 67385 Problem Description I have a very simple problem for you. Given two integers A and B, you…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1002 题意: 数学题,A+B; 思路,这个数非常大,普通加法一定会超时,所以用大数加法.大数加法的基本思路是模拟我们做加法的时候的进位思想,从最低位开始模拟, 在我的代码里 v -- 进位, tmp -- 当前位2个数的和,k -- 答案数组的下标. 其中, tmp/10 可以得到要进的位数, 同理,tmp%10可以得到个位,就是答案数组对应的位 下面是AC代码: #include <iostre…

Exponentiation Time Limit: 1000/500 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 6973    Accepted Submission(s): 1975 Problem Description Problems involving the computation of exact values of very large magnitude…

HDU1002:大数加法,PE了N次 import java.util.Scanner; import java.math.*; public class Main { public static void main(String[] args) { Scanner cin = new Scanner(System.in); int T; T=cin.nextInt(); for(int z=1;z<=T;z++) { if(z!=1) System.out.println(); BigInte…