You are given a string representing an attendance record for a student. The record only contains the following three characters: 'A' : Absent. 'L' : Late. 'P' : Present. A student could be rewarded if his attendance record doesn't contain more than o…

题目: You are given a string representing an attendance record for a student. The record only contains the following three characters: 'A' : Absent. 'L' : Late. 'P' : Present. A student could be rewarded if his attendance record doesn't contain more th…

551. Student Attendance Record I[easy] You are given a string representing an attendance record for a student. The record only contains the following three characters: 'A' : Absent. 'L' : Late. 'P' : Present. A student could be rewarded if his attend…

problem 551. Student Attendance Record I 题意: solution: class Solution { public: bool checkRecord(string s) { ; ; for(auto ch:s) { if('A'==ch) { ) return false;// cntL = ;// } else if('L' == ch) { ) return false;// } ;// } return true; } }; 理解题意很简单,重要…

Given a positive integer n, return the number of all possible attendance records with length n, which will be regarded as rewardable. The answer may be very large, return it after mod 109 + 7. A student attendance record is a string that only contain…

［抄题］: You are given a string representing an attendance record for a student. The record only contains the following three characters: 'A' : Absent. 'L' : Late. 'P' : Present. A student could be rewarded if his attendance record doesn't contain more…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 正则表达式 统计 日期 题目地址:https://leetcode.com/problems/student-attendance-record-i/#/description 题目描述 You are given a string representing an attendance record for a student. The record…

You are given a string representing an attendance record for a student. The record only contains the following three characters: 'A' : Absent. 'L' : Late. 'P' : Present. A student could be rewarded if his attendance record doesn't contain more than o…

▶ 一个学生的考勤状况是一个字符串,其中各字符的含义是:A 缺勤,L 迟到,P 正常.如果一个学生考勤状况中 A 不超过一个,且没有连续两个 L(L 可以有多个,但是不能连续),则称该学生达标(原文表述:A student could be rewarded if his attendance record doesn't contain more than one 'A' (absent) or more than two continuous 'L' (late). ) ▶ 551. 给定一…

1.题目描述 You are given a string representing an attendance record for a student. The record only contains the following three characters: 'A' : Absent. 'L' : Late. 'P' : Present. A student could be rewarded if his attendance record doesn't contain more…

给定一个字符串来代表一个学生的出勤纪录,这个纪录仅包含以下三个字符:    'A' : Absent,缺勤    'L' : Late,迟到    'P' : Present,到场如果一个学生的出勤纪录中不超过一个'A'(缺勤)并且不超过两个连续的'L'(迟到),那么这个学生会被奖赏.你需要根据这个学生的出勤纪录判断他是否会被奖赏.示例 1:输入: "PPALLP"输出: True 示例 2:输入: "PPALLL"输出: False详见:https://leetc…

static int wing=[]() { std::ios::sync_with_stdio(false); cin.tie(NULL); ; }(); class Solution { public: bool checkRecord(string s) { ; int len=s.length(); ;i<len;i++) { if(s[i]=='A') countA++; if(s[i]=='L') { <len&&s[i+]==]=='L') return fals…

Given a positive integer n, return the number of all possible attendance records with length n, which will be regarded as rewardable. The answer may be very large, return it after mod 109 + 7. A student attendance record is a string that only contain…

题目如下: Given a positive integer n, return the number of all possible attendance records with length n, which will be regarded as rewardable. The answer may be very large, return it after mod 109 + 7. A student attendance record is a string that only c…

Given a positive integer n, return the number of all possible attendance records with length n, which will be regarded as rewardable. The answer may be very large, return it after mod 109 + 7. A student attendance record is a string that only contain…

Given a positive integer n, return the number of all possible attendance records with length n, which will be regarded as rewardable. The answer may be very large, return it after mod 109 + 7. A student attendance record is a string that only contain…

You are given a string representing an attendance record for a student. The record only contains the following three characters: 'A' : Absent. 'L' : Late. 'P' : Present. A student could be rewarded if his attendance record doesn't contain more than o…

原题链接在这里:https://leetcode.com/problems/student-attendance-record-i/description/ 题目: You are given a string representing an attendance record for a student. The record only contains the following three characters: 'A' : Absent. 'L' : Late. 'P' : Presen…

描述 You are given a string representing an attendance record for a student. The record only contains the following three characters: 'A' : Absent. 'L' : Late. 'P' : Present. A student could be rewarded if his attendance record doesn't contain more tha…

问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3953 访问. 给定一个字符串来代表一个学生的出勤纪录,这个纪录仅包含以下三个字符: 'A' : Absent,缺勤 'L' : Late,迟到 'P' : Present,到场 如果一个学生的出勤纪录中不超过一个'A'(缺勤)并且不超过两个连续的'L'(迟到),那么这个学生会被奖赏. 你需要根据这个学生的出勤纪录判断他是否会被奖赏. 输入: "PPALLP&qu…

You are given a string representing an attendance record for a student. The record only contains the following three characters: 'A' : Absent. 'L' : Late. 'P' : Present. A student could be rewarded if his attendance record doesn't contain more than o…

这是悦乐书的第258次更新,第271篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第125题(顺位题号是551).您将获得一个表示学生出勤记录的字符串. 该记录仅包含以下三个字符: 'A':缺席. 'L':迟到. 'P':在场. 如果学生的出勤记录不超过一个"A"(缺席)或超过两个连续的"L"(迟到),则可以奖励学生.您需要返回学生是否可以根据他的出勤记录获得奖励.例如: 输入:"PPALLP" 输出:true 输入…

给定一个正整数 n,返回长度为 n 的所有可被视为可奖励的出勤记录的数量. 答案可能非常大,你只需返回结果mod 109 + 7的值.学生出勤记录是只包含以下三个字符的字符串:    1.'A' : Absent,缺勤    2.'L' : Late,迟到    3.'P' : Present,到场如果记录不包含多于一个'A'(缺勤)或超过两个连续的'L'(迟到),则该记录被视为可奖励的.示例:输入: n = 2输出: 8 解释:有8个长度为2的记录将被视为可奖励:"PP" , &qu…

给定一个字符串来代表一个学生的出勤纪录,这个纪录仅包含以下三个字符: 'A' : Absent,缺勤 'L' : Late,迟到 'P' : Present,到场 如果一个学生的出勤纪录中不超过一个'A'(缺勤)并且不超过两个连续的'L'(迟到),那么这个学生会被奖赏. 你需要根据这个学生的出勤纪录判断他是否会被奖赏. 示例 1: 输入: "PPALLP" 输出: True 示例 2: 输入: "PPALLL" 输出: False class Solution {…

You are given a string representing an attendance record for a student. The record only contains the following three characters: 'A' : Absent. 'L' : Late. 'P' : Present. A student could be rewarded if his attendance record doesn't contain more than o…

题目描述: You are given a string representing an attendance record for a student. The record only contains the following three characters: 'A' : Absent. 'L' : Late. 'P' : Present. A student could be rewarded if his attendance record doesn't contain more…

551. 学生出勤记录 I 给定一个字符串来代表一个学生的出勤记录,这个记录仅包含以下三个字符: 'A' : Absent,缺勤 'L' : Late,迟到 'P' : Present,到场 如果一个学生的出勤记录中不超过一个'A'(缺勤)并且不超过两个连续的'L'(迟到),那么这个学生会被奖赏. 你需要根据这个学生的出勤记录判断他是否会被奖赏. 示例 1: 输入: "PPALLP" 输出: True 示例 2: 输入: "PPALLL" 输出: False cla…

463. Island Perimeterhttps://leetcode.com/problems/island-perimeter/就是逐一遍历所有的cell,用分离的cell总的的边数减去重叠的边的数目即可.在查找重叠的边的数目的时候有一点小技巧,就是沿着其中两个方向就好,这种题目都有类似的规律,就是可以沿着上三角或者下三角形的方向来做.一刷一次ac,但是还没开始注意codestyle的问题,需要再刷一遍. class Solution { public: int islandPerime…

突然很想刷刷题,LeetCode是一个不错的选择,忽略了输入输出,更好的突出了算法,省去了不少时间. dalao们发现了任何错误,或是代码无法通过,或是有更好的解法,或是有任何疑问和建议的话,可以在对应的随笔下面评论区留言,我会及时处理,在此谢过了. 过程或许会很漫长,也很痛苦,慢慢来吧. 编号 题名 过题率 难度 1 Two Sum 0.376 Easy 2 Add Two Numbers 0.285 Medium 3 Longest Substring Without Repeating C…

All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) .   Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…