题目:Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. struct ListNode { int val; ListNode *next; ListNode(int x) : val(x), next(NULL) {} }; ListNode *mergeTwoL…

Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 题目意思: 合并K条已经排序的链表.分析时间复杂度. 解题思路: 很容易就想起之前学的合并两条链表的算法,这一题其实就是那个题目的扩展,变成合并K条了.我采用的方法就是迭代法. 如果只有一条,直接返回.如果只有两条,就只需要调用mergeTwo一下.如果超过两…

描述 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example: Input: [   1->4->5,   1->3->4,   2->6 ] Output: 1->1->2->3->4->4->5->6 思路 借鉴Merge Two Sorted Lists的解决思路,对两个数…

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 类似于归并2个链表,暴力一点的方法就是,每取出一个list就与以前的list归并返回merge后list,知道所有list merge完成. 但是可惜,这样做会TLE.贴下代码先: /** * Definition for singly-linked list. * struct ListNode {…

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 注意题目要求合并的时候不能新建节点,直接使用原来的节点,比较简单,代码如下: /** * Definition for singly-linked list. * struct ListNode { * int va…

Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity.   采用优先队列priority_queue 把ListNode放入优先队列中,弹出最小指后,如果该ListNode有下一个元素,则把下一个元素放入到队列中     /** * Definition for singly-linked list. * stru…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 21: Merge Two Sorted Listshttps://oj.leetcode.com/problems/merge-two-sorted-lists/ Merge two sorted linked lists and return it as a new list.The new list should be made by splicing together…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 23: Merge k Sorted Listshttps://oj.leetcode.com/problems/merge-k-sorted-lists/ Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. ===Comments…

这两天一直也没有顾上记录一下自己做过的题目,回头看看,感觉忘的好快,今天做了一个hard,刚开始觉得挺难得,想了两种方法,一种是每次都从k个list中选取最小的一个,为空的直接跳过,再就是每次合并其中的两个list,直到最终合并完成,这就要用到地柜的方法,还有就是划分,感觉递归的思路比较清晰,就拿地柜的写了,使用递归的方法,这道题目就是以21. Merge Two Sorted Lists  为基础的. 阶梯思路就是,每次都从中间切割lists,直到切割完之后左侧或者右侧为,一个或者两个list…

21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 代…