poj--2553--The Bottom of a Graph (scc+缩点）

【poj--2553--The Bottom of a Graph (scc+缩点）】的更多相关文章

POJ 2553 The Bottom of a Graph（强连通分量）

POJ 2553 The Bottom of a Graph 题目链接题意:给定一个有向图,求出度为0的强连通分量思路:缩点搞就可以代码: #include <cstdio> #include <cstring> #include <algorithm> #include <vector> #include <stack> using namespace std; const int N = 5005; int n, m; vector&l…

poj 2553 The Bottom of a Graph(强连通分量+缩点)

题目地址:http://poj.org/problem?id=2553 The Bottom of a Graph Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 7881 Accepted: 3263 Description We will use the following (standard) definitions from graph theory. Let V be a nonempty and finit…

poj 2553 The Bottom of a Graph【强连通分量求汇点个数】

The Bottom of a Graph Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 9641 Accepted: 4008 Description We will use the following (standard) definitions from graph theory. Let V be a nonempty and finite set, its elements being called ver…

POJ 2553 The Bottom of a Graph (强连通分量)

题目地址:POJ 2553 题目意思不好理解.题意是:G图中从v可达的全部点w,也都能够达到v,这种v称为sink.然后升序输出全部的sink. 对于一个强连通分量来说,全部的点都符合这一条件,可是假设这个分量还连接其它分量的话,则肯定都不是sink.所以仅仅须要找出度为0的强连通分量就可以. 代码例如以下: #include <iostream> #include <string.h> #include <math.h> #include <queue>…

POJ 2553 The Bottom of a Graph (Tarjan）

The Bottom of a Graph Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 11981 Accepted: 4931 Description We will use the following (standard) definitions from graph theory. Let V be a nonempty and finite set, its elements being called ve…

POJ 2553 The Bottom of a Graph Tarjan找环缩点(题解解释输入)

Description We will use the following (standard) definitions from graph theory. Let V be a nonempty and finite set, its elements being called vertices (or nodes). Let E be a subset of the Cartesian product V×V, its elements being called edges. Then G…