Word Amalgamation Time Limit: 1 Sec  Memory Limit: 64 MB Submit: 373  Solved: 247 Description In millions of newspapers across the United States there is a word game called Jumble. The object of this game is to solve a riddle, but in order to find th…

Word Amalgamation Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 9794   Accepted: 4701 Description In millions of newspapers across the United States there is a word game called Jumble. The object of this game is to solve a riddle, but…

传送门:ZOJ1181  思路:自身排序来判断两个字符串拥有相同的字符.   #include<cstdio> #include<cstdlib> #include<iostream> #include<cstring> #include<string> #include<cmath> #include<memory.h> #include<algorithm> using namespace std; str…

Word Amalgamation Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2586    Accepted Submission(s): 1246 Problem Description In millions of newspapers across the United States there is a word game…

版权声明:本文为博主原创文章.未经博主同意不得转载. vasttian https://blog.csdn.net/u012860063/article/details/35338617 转载请注明出处:http://blog.csdn.net/u012860063天资 题目链接:http://acm.hdu.edu.cn/showproblem.php? pid=1113 postid=17794&messageid=1&deep=0" rel="nofollow&q…

Word Amalgamation 点我挑战题目 点我一起学习STL-MAP 题意分析 给出字典.之后给出一系列======乱序======单词,要求你查字典,如过这个乱序单词对用有多个有序单词可以输出,那么按照字典序将其输出. 若没有对应单词,输出NOT A VALID WORD. 可见这是一组组对应关系,可以用map来实现.map字典中first保存原本的单词(因为first按字典序),second保存原本单词排序后的单词.每次读入一个乱序单词后,sort遍历map并查找和second匹配的…

Word Amalgamation Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 9968   Accepted: 4774 Description In millions of newspapers across the United States there is a word game called Jumble. The object of this game is to solve a riddle, but…

 Word Amalgamation  In millions of newspapers across the United States there is a word game called Jumble. The object of this game is to solve a riddle, but in order to find the letters that appear in the answer it is necessary to unscramble four wor…

// EnumSort.cpp : 定义控制台应用程序的入口点. //枚举排序 /* 枚举排序(Enumeration Sort)是一种最简单的排序算法,通常也称为秩排序(Rank Sort). 该算法的具体思想是(假设按关键字递增排序),对每一个待排序的元素统计小于它的所有元素的个数,从而得到该元素最终处于序列中的位置. 假定待排序的n个数存在a[1]-a[n]中.首先将a[1]与a[2]-a[n]比较,记录比其小的数的个数,令其为k, a[1]就被存入有序的数组b[1]-b[n]的b[k+1…

Word Amalgamation Problem Description In millions of newspapers across the United States there is a word game called Jumble. The object of this game is to solve a riddle, but in order to find the letters that appear in the answer it is necessary to u…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1113 题意:输入一个字典,然后再输入若干单词(每行中,1 <= 单词数 <= 100,并且每个单词在字典中保证是唯一的),用XXXXXX结尾来表示字典的结束.接着输入一个单词word(1 <= 字母个数 <= 6),每个单词你都需要在字典中找出所有可以用word的字母重排后得到的单词,并按照字典序从小到大的顺序在一行中输出:如果不存在,则输出“NOT A VALID WORD”.注意:…

Problem Description In millions of newspapers across the United States there is a word game called Jumble. The object of this game is to solve a riddle, but in order to find the letters that appear in the answer it is necessary to unscramble four wor…

Description In millions of newspapers across the United States there is a word game called Jumble. The object of this game is to solve a riddle, but in order to find the letters that appear in the answer it is necessary to unscramble four words. Your…

标题:神奇算式 由4个不同的数字,组成的一个乘法算式,它们的乘积仍然由这4个数字组成. 比如: 210 x 6 = 1260 8 x 473 = 3784 27 x 81 = 2187 都符合要求. 如果满足乘法交换律的算式算作同一种情况,那么,包含上边已列出的3种情况,一共有多少种满足要求的算式. 请填写该数字,通过浏览器提交答案,不要填写多余内容(例如:列出所有算式). 这里的思路:枚举4个数字,判断两两数的乘积是否等于 这4个数组成的某个数字(判断相等,可以先用字符串排序,只要满足 A(a…

http://acm.hdu.edu.cn/showproblem.php?pid=1113 给定一个字典,然后每次输入一个字符串问字典中是否有单词与给定的字符串的所有字母一样(顺序可以打乱),按字典序输出字典中的原字符串. 我开始是直接用了 sort, 用一个结构体记录了所有字符串,和相应下标,输出的时候在用了冒泡排序. #include <iostream> #include <cstdio> #include <cmath> #include <vector…

题目:给你一个单词列表.再给你一些新的单词.输出列表中又一次排列能得到此新单词的词. 分析:字符串.对每一个字符串的字母排序生成新的传f(str).总体排序,用二分来查找就可以. 说明:注意输出要满足字典序,先排序后查找. #include <algorithm> #include <iostream> #include <cstdlib> #include <cstring> #include <cstdio> using namespace…

http://acm.hdu.edu.cn/showproblem.php?pid=1113 Problem Description In millions of newspapers across the United States there is a word game called Jumble. The object of this game is to solve a riddle, but in order to find the letters that appear in th…

原题链接:http://acm.hdu.edu.cn/showproblem.php?pid=1113 字符串简单题: stl水过 如下: #include<algorithm> #include<iostream> #include<cstdlib> #include<cstring> #include<cstdio> #include<string> #include<map> #include<set>…

Problem Description In millions of newspapers across the United States there is a word game called Jumble. The object of this game is to solve a riddle, but in order to find the letters that appear in the answer it is necessary to unscramble four wor…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1113 找单词 #include <iostream> #include <string> #include <map> #include <algorithm> using namespace std; map<string, string> str; string s, t; int main() { while(cin >> s &a…

文件转自:http://www.2cto.com/os/201303/197829.html ls按时间排序输出文件列表   首先,ls --help查看ls相关的与时间排序相关的参数:   > ls --help|grep -E "time|sort" 如果不指定 -cftuSUX 或 --sort 任何一个选项,则根据字母大小排序.   -c                         配合 -lt:根据 ctime 排序及显示 ctime (文件            …

                        第2章Office解决方案介绍 Office解决方案的三种基本模式现在,您了解Office对象模型的基本模式,本章将介绍开发人员如何模拟和构建其Office解决方案. 使用Office构建的大多数解决方案都遵循三种模式之一 Office 自动化执行 Office 加载项 Office 文档背后的代码 一个自动化可执行文件是一个独立于Office控制和自动化Office应用程序的程序.可以使用Visual Studio等开发工具创建自动化可执行文件.…

Problem Description Talented Mr.Tang has n strings consisting of only lower case characters. He wants to charge them with Balala Power (he could change each character ranged from a to z into each number ranged from 0 to 25, but each two different cha…

DescriptionCraig is fond of planes. Making photographs of planes forms a major part of his daily life. Since he tries to stimulate his social life, and since it’s quite a drive from his home to the airport, Craig tries to be very efficient by investi…

总结:一种简单的交换顺序,从数左边开始扫描待排序的元素,在扫描过程中依次对相邻元素进行比较,将较大值后移,每经过一轮排序后,值最大的元素将移到末尾, 此时记下该元素的位置,下一轮排序只需比较到此位置即可,如此重复,直到比较最后两个元素. 对个元素冒泡排序,总共需要进行n-1轮,第1轮需要比较n-1次,第2轮需要比较n-2次,第i轮需要比较n-i次,最后一轮需要比较1次 package com.aini; //5.给你一组字符如{1,3,4,7,2,1,1,5,2}, //让你输出里面出现次数最多…

Given an array of words and a length L, format the text such that each line has exactly L characters and is fully (left and right) justified. You should pack your words in a greedy approach; that is, pack as many words as you can in each line. Pad ex…

题意:一个 L*R 的网格里有 N 棵树,要求找一个最大空正方形并输出其左下角坐标和长.(1≤L,R≤10000, 0≤N≤100) 解法:枚举空正方形也就是枚举空矩阵,先要固定一个边,才好继续操作.(P.S.许多类型的题都是这样:先固定一个变量,再比较另外的变量.也就是我之前提到过的"部分枚举".这种思想在贪心.DP等都常出现,一定要掌握!)所以这题就是先枚举一条边的范围(横坐标),再枚举排序后的点,根据当前枚举的点和之前纵坐标最大的点的纵坐标得到这条边的长度,再比较.更新答案. P…

acm之pku题目分类 对ACM有兴趣的同学们可以看看 DP:  1011   NTA                 简单题  1013   Great Equipment     简单题  1024   Calendar Game       简单题  1027   Human Gene Functions   简单题  1037   Gridland            简单题  1052   Algernon s Noxious Emissions 简单题  1409   Commun…

以下是poj百道水题,新手可以考虑从这里刷起 搜索1002 Fire Net1004 Anagrams by Stack1005 Jugs1008 Gnome Tetravex1091 Knight Moves1101 Gamblers1204 Additive equations 1221 Risk1230 Legendary Pokemon1249 Pushing Boxes 1364 Machine Schedule1368 BOAT1406 Jungle Roads1411 Annive…

Codeforces Round #371 (Div. 2) A. Meeting of Old Friends |B. Filya and Homework A. Meeting of Old Friends  模拟 #include <iostream> #include <cstdio> #include <algorithm> #include <cstring> using namespace std; typedef long long ll;…