Day2-G-Sticks-POJ1011 - 相关文章

【Day2-G-Sticks-POJ1011】的更多相关文章

python学习第二天 -----2019年4月17日

第二周-第02章节-Python3.5-模块初识 #!/usr/bin/env python #-*- coding:utf-8 _*- """ @author:chenjisong @file: sys.py @time: 2019/04/16 url:https://www.liaoxuefeng.comfunctions:Software:JetBrains PyCharm 4.5.3"""#import guessimport osimp…

DFS系列 POJ(自认为的讲解)

C - Sum It Up POJ1564 题意: 给你一个N,然后给你一堆数The numbers in each list appear in nonincreasing order, and there may be repetitions.,让你在这对数里找出一些数,如果他们的和sum==N,则按样例的格式数输出. 思路: 那就是DFS呗,深搜一波,当sum==N时就输出,这里有一个就是排除重复的剪枝.为什么呢? #include<iostream> #include<cstdi…

Storyboards Tutorial 03

这一节主要介绍segues,static table view cells 和 Add Player screen 以及 a game picker screen. Introducing Segues 开启 Main.storyboard拖拉一个Bar Button Item到Players窗口导航栏的右侧.在Attributes inspector中改变Identifier为Add,就会出现一个+号button.…

文件图标SVG

poj1011 Sticks (搜索经典好题)

poj1011 Sticks 题目连接: poj1011 Description George took sticks of the same length and cut them randomly until all parts became at most 50 units long. Now he wants to return sticks to the original state, but he forgot how many sticks he had originally an…

【poj1011】 Sticks

http://poj.org/problem?id=1011 (题目链接) 题意给出一大堆小棍子的长度,需要把他们拼成几根长度相等的大棍子,求大棍子的最短长度. Solution 经典搜索题,剪枝剪到手软. 要得到最小的原始木棍长度,可以按照分段数的长度,依次枚举所有的可能长度L.每次枚举L时,dfs判断是否能用小木棍拼合出整数个L.如果不剪枝,就等着狂TLE吧. 最优性: 1.所有木棍的长度和一定能一定能整除大木棍长度L. 2.大木棍长度一定>=小木棍最长长度. 可行性: 3.一只长木棍肯定…

POJ1011 Sticks

Description George took sticks of the same length and cut them randomly until all parts became at most 50 units long. Now he wants to return sticks to the original state, but he forgot how many sticks he had originally and how long they were original…