Day2-G-Sticks-POJ1011】的更多相关文章

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C - Sum It Up POJ1564 题意: 给你一个N,然后给你一堆数The numbers in each list appear in nonincreasing order, and there may be repetitions.,让你在这对数里找出一些数,如果他们的和sum==N,则按样例的格式数输出. 思路: 那就是DFS呗,深搜一波,当sum==N时就输出,这里有一个就是排除重复的剪枝.为什么呢? #include<iostream> #include<cstdi…
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poj1011 Sticks 题目连接: poj1011 Description George took sticks of the same length and cut them randomly until all parts became at most 50 units long. Now he wants to return sticks to the original state, but he forgot how many sticks he had originally an…
http://poj.org/problem?id=1011 (题目链接) 题意 给出一大堆小棍子的长度,需要把他们拼成几根长度相等的大棍子,求大棍子的最短长度. Solution 经典搜索题,剪枝剪到手软. 要得到最小的原始木棍长度,可以按照分段数的长度,依次枚举所有的可能长度L.每次枚举L时,dfs判断是否能用小木棍拼合出整数个L.如果不剪枝,就等着狂TLE吧. 最优性: 1.所有木棍的长度和一定能一定能整除大木棍长度L. 2.大木棍长度一定>=小木棍最长长度. 可行性: 3.一只长木棍肯定…
Description George took sticks of the same length and cut them randomly until all parts became at most 50 units long. Now he wants to return sticks to the original state, but he forgot how many sticks he had originally and how long they were original…
Sticks Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 110416   Accepted: 25331 Description George took sticks of the same length and cut them randomly until all parts became at most 50 units long. Now he wants to return sticks to the or…
题目链接 http://poj.org/problem?id=1011 题意 输入n根棍子的长度,将这n根棍子组合成若干根长度相同的棍子,求组合后的棍子的最小长度.这题是poj2362的加强版,思路与poj2362相同,只是在2362的基础上添加了剪枝操作,做这题之前先去做poj2362效果最好. 思路 由于棍子越长,组合时的灵活性越差,所以要先从长棍子开始搜索,则首先要将n根棍子从长到短排序,然后从最长的棍子开始dfs.由于棍子最多可以有64根,不剪枝的话肯定会超时.以下是几种剪枝方法: (1…
https://vjudge.net/problem/POJ-1011 此题很重要.★★★ 很欢(e)乐(xin)的一道搜索剪枝题..poj数据还是太水了,我后来想不出来剪枝方法了,就加了句掐了时间语句交上去骗了一个AC..洛谷上加强数据掉了4个点. 由题意(翻译)  ,要确定一个长度让所有短木棍拼的出来.由于数据看起来很小N只有64,所以要搜索.但是怎么搜还是关键.由于枚举长度不满足答案单调性,所以不好二分,只能从小到大枚举,找到就输出.每次check的dfs就是看可不可以选出恰好拼出一根长度…