A. time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Rock... Paper! After Karen have found the deterministic winning (losing?) strategy for rock-paper-scissors, her brother, Koyomi, comes up…
A. The Artful Expedient 题目链接http://codeforces.com/contest/869/problem/A 解题心得:就是一个水题,读懂题就好,题意是,(i,j)ai异或bi,统计ai异或bi得到的数能够在ai或bi中找的个数,如果是偶数输出Karen,否则输出Karen. #include<bits/stdc++.h> using namespace std; const int maxn = 20000; const int maxn2 = 2e7+10…
A. The Artful Expedient time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Rock... Paper! After Karen have found the deterministic winning (losing?) strategy for rock-paper-scissors, her broth…
A. The Artful Expedient time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Rock... Paper! After Karen have found the deterministic winning (losing?) strategy for rock-paper-scissors, her broth…
Rock... Paper! After Karen have found the deterministic winning (losing?) strategy for rock-paper-scissors, her brother, Koyomi, comes up with a new game as a substitute. The game works as follows. A positive integer n is decided first. Both Koyomi a…
time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Rock... Paper! After Karen have found the deterministic winning (losing?) strategy for rock-paper-scissors, her brother, Koyomi, comes up wit…
A. The Artful Expedient 题目链接:http://codeforces.com/contest/869/problem/A 题目意思:给你两个数列,各包含n个数,现在让你从上下两个数列中各取一个数a[i],b[j],如果a[i]^b[j]在这2×n个数里面出现过,那么就获得一分,问将任意的a[i],b[j]之间的亦或之后,如果分数是奇数则Koyomi胜利,否则Karen胜利.问最后到底谁胜了. 题目思路:非常无聊的题目,暴力都可以过,就是暴力枚举a[i],b[j],把所有答…
