A 和 B 在一个 3 x 3 的网格上玩井字棋. 井字棋游戏的规则如下: 玩家轮流将棋子放在空方格 (" ") 上.第一个玩家 A 总是用 "X" 作为棋子,而第二个玩家 B 总是用 "O" 作为棋子."X" 和 "O" 只能放在空方格中,而不能放在已经被占用的方格上.只要有 3 个相同的(非空)棋子排成一条直线(行.列.对角线)时,游戏结束.如果所有方块都放满棋子(不为空),游戏也会结束.游戏结束后,棋…
题目描述: 自己的提交: class Solution: def tictactoe(self, moves: List[List[int]]) -> str: p = [[0] * 3 for _ in range(3)] if len(moves) < 5: return "Pending" for i in moves[::2]: p[i[0]][i[1]] = "X" for i in moves[1::2]: p[i[0]][i[1]] = &…
A Tic-Tac-Toe board is given as a string array board. Return True if and only if it is possible to reach this board position during the course of a valid tic-tac-toe game. The board is a 3 x 3 array, and consists of characters " ", "X"…
A Tic-Tac-Toe board is given as a string array board. Return True if and only if it is possible to reach this board position during the course of a valid tic-tac-toe game. The board is a 3 x 3 array, and consists of characters " ", "X"…
Design a Tic-tac-toe game that is played between two players on a n x n grid. You may assume the following rules: A move is guaranteed to be valid and is placed on an empty block.Once a winning condition is reached, no more moves is allowed.A player…
17.2 Design an algorithm to figure out if someone has won a game oftic-tac-toe. 这道题让我们判断玩家是否能赢井字棋游戏,有下面几点需要考虑: 1. 判断是否能赢hasWon函数是调用一次还是多次,如果是多次,我们可能为了优化而需要加入一些预处理. 2. 井字棋游戏通常是3x3的大小,我们是否想要实现NxN的大小? 3. 我们需要在代码紧凑,执行速度和代码清晰之间做出选择. #include <iostream> #…
一个很经典的井字棋游戏 Pascal源码Chaobs奉上 注意:1.有的FP版本不支持汉语,将会出现乱码.2.别想赢电脑了,平手不错了. 井字过三关: program TicTacToe; uses crt; var a:Array [1..3] of Array [1..3] of char; b:Array [1..3] of Array [1..3] of integer; i,n,g,e,p:integer; t:text; c:char; o:integer; r:integer; s…
利用JavaFX设计一个井字棋游戏,其中包括了能够与玩家对战的AI.AI的实现相比五子棋来说要简单得多,可以保证AI在后手情况下绝对不会输,具体实现如下: /* * To change this license header, choose License Headers in Project Properties. * To change this template file, choose Tools | Templates * and open the template in the ed…
