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PAT A1046 Shortest Distance 标签(空格分隔): PAT TIPS: 最后一个数据点可能会超时 #include <cstdio> #include <algorithm> using namespace std; const int maxn = 100010; int d[maxn], dist[maxn]; int main() { int total = 0, n; scanf("%d", &n); for(int i…
The task is really simple: given N exits on a highway which forms a simple cycle, you are supposed to tell the shortest distance between any pair of exits. Input Specification: Each input file contains one test case. For each case, the first line con…
17/20,部分超时. #include<bits/stdc++.h> using namespace std; int N,x,pairs; int a,b; vector<int> dist; void input(){ cin>>N; for(int i=0;i<N;i++){ cin>>x; dist.push_back(x); } } void solve(){ cin>>pairs; for(int i=0;i<pairs…
1046 Shortest Distance (20)(20 分)提问 The task is really simple: given N exits on a highway which forms a simple cycle, you are supposed to tell the shortest distance between any pair of exits. Input Specification: Each input file contains one test cas…
题目提交一直出现段错误,经过在网上搜索得知是数组溢出,故将数组设置的大一点 AC代码 #include <cstdio> #include <algorithm> #define N 11000 using namespace std; int main(){ #ifdef ONLINE_JUDGE #else freopen("1.txt", "r", stdin); #endif // ONLINE_JUDGE int dis[N]; i…
n个节点围成一个环,每个节点之间的距离已知.输入n并给出n个节点的距离,输入m组节点编号(两个),求这两个节点编号间的最短距离. 1 建立dis[]数组,记录V1点到每一个点的顺时针距离,sum计算环的总距离. 2 输入m组节点编号,如果左边的值大于右边的值,则使用swap()函数将其交换. 3 计算temp=dis[right-1]-dis[left-1],比较temp和sum-temp,输出最小的即为最短距离. 注1:swap()函数即将两个变量交换:swap(a,b): 注2:#inclu…
The task is really simple: given N exits on a highway which forms a simple cycle, you are supposed to tell the shortest distance between any pair of exits. Input Specification: Each input file contains one test case. For each case, the first line con…
B1018. 锤子剪刀布 (20) Discription: 大家应该都会玩"锤子剪刀布"的游戏:两人同时给出手势,胜负规则如图所示: 现给出两人的交锋记录,请统计双方的胜.平.负次数,并且给出双方分别出什么手势的胜算最大. Input: 输入第1行给出正整数N(<=105),即双方交锋的次数.随后N行,每行给出一次交锋的信息,即甲.乙双方同时给出的的手势.C代表"锤子".J代表"剪刀".B代表"布",第1个字母代表甲方…
1046 Shortest Distance (20 分) The task is really simple: given N exits on a highway which forms a simple cycle, you are supposed to tell the shortest distance between any pair of exits. Input Specification: Each input file contains one test case. For…
题目AC汇总 甲级AC PAT A1001 A+B Format (20 分) PAT A1002 A+B for Polynomials(25) PAT A1005 Spell It Right (20) PAT A1006 Sign In and Sign Out (25) PAT A1009 Product of Polynomials(25) PAT A1011 World Cup Betting(20) PAT A1012 Best Rank(25) PAT A1016 Phone B…
专题一  字符串处理 A1001 Format(20) #include<cstdio> int main () { ]; int a,b,sum; scanf ("%d %d",&a,&b); sum=a+b; ) { printf ("-"); sum=-sum; } ; ) { s[top++]=; } ) { s[top++]=sum%; sum/=; } ;i>=;i--) { printf ("%d"…