这是悦乐书的第370次更新,第398篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第232题(顺位题号是985).有一个整数数组A和一个查询数组queries. 对于第i个查询val = queries[i][0],index = queries[i][1],我们将val添加到A[index].然后,第i个查询的答案是A的偶数值的总和.(这里给定的index = queries[i][1]是一个基于0的索引,每个查询都会修改数组A.) 返回所有查询的答案.你的答案数…

package y2019.Algorithm.array; /** * @ProjectName: cutter-point * @Package: y2019.Algorithm.array * @ClassName: SumEvenAfterQueries * @Author: xiaof * @Description: 985. Sum of Even Numbers After Queries * * We have an array A of integers, and an arr…

problem 985. Sum of Even Numbers After Queries class Solution { public: vector<int> sumEvenAfterQueries(vector<int>& A, vector<vector<int>>& queries) { vector<int> res; ; ==) sum +=a; for(auto query:queries) { ]]%== )…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 暴力 找规律 日期 题目地址:https://leetcode.com/problems/sum-of-even-numbers-after-queries/ 题目描述 We have an array A of integers, and an array queries of queries. For the i-th query val = q…

We have an array A of integers, and an array queries of queries. For the i-th query val = queries[i][0], index = queries[i][1], we add val to A[index]. Then, the answer to the i-th query is the sum of the even values of A. (Here, the given index = qu…

Difficulty: Easy Question We have an array A of integers, and an array queries of queries. For the i-th query val = queries[i][0], index = queries[i][1], we add val to A[index]. Then, the answer to the i-th query is the sum of the even values of A. (…

We have an array A of integers, and an array queries of queries. For the i-th query val = queries[i][0], index = queries[i][1], we add val to A[index].  Then, the answer to the i-th query is the sum of the even values of A. (Here, the given index = q…

题目如下: We have an array A of integers, and an array queries of queries. For the i-th query val = queries[i][0], index = queries[i][1], we add val to A[index].  Then, the answer to the i-th query is the sum of the even values of A. (Here, the given ind…

https://leetcode.com/problems/sum-of-even-numbers-after-queries/ We have an array A of integers, and an array queries of queries. For the i-th query val = queries[i][0], index = queries[i][1], we add val to A[index].  Then, the answer to the i-th que…

题目要求 We have an array A of integers, and an array queries of queries. For the i-th query val = queries[i][0], index = queries[i][1], we add val to A[index].  Then, the answer to the i-th query is the sum of the even values of A. (Here, the given inde…