STL中的list就是一双向链表,可高效地进行插入删除元素. List 是 C++标准程式库 中的一个 类 ,可以简单视之为双向 连结串行 ,以线性列的方式管理物件集合.list 的特色是在集合的任何位置增加或删除元素都很快,但是不支持随机存取.list 是 C++标准程式库 提供的众多容器(container)之一,除此之外还有 vector .set.map.…等等.list 以模板方式实现(即泛型),可以处理任意型别的变量,包括使用者自定义的资料型态,例如:它可以是一个放置整数(int)型…

Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. Note:Try to come up as many solutions as you can, there are at least 3 different ways to solve this pro…

Given a list, rotate the list to the right by k places, where k is non-negative. For example:Given 1->2->3->4->5->NULL and k = 2,return 4->5->1->2->3->NULL. 这道旋转链表的题和之前那道Rotate Array 旋转数组 很类似,但是比那道要难一些,因为链表的值不能通过下表来访问,只能一个一个的…

You are given an n x n 2D matrix representing an image. Rotate the image by 90 degrees (clockwise). Follow up:Could you do this in-place? 在计算机图像处理里,旋转图片是很常见的,由于图片的本质是二维数组,所以也就变成了对数组的操作处理,翻转的本质就是某个位置上数移动到另一个位置上,比如用一个简单的例子来分析: 1  2  3 7  4  1 4  5  6 -…

Given a list, rotate the list to the right by k places, where k is non-negative. For example: Given 1->2->3->4->5->NULL and k = 2, return 4->5->1->2->3->NULL. 原题链接:https://oj.leetcode.com/problems/rotate-list/ 得到链表长度.链表指向尾节点,…

48. Rotate Image     Total Accepted: 69437 Total Submissions: 198781 Difficulty: Medium You are given an n x n 2D matrix representing an image. Rotate the image by 90 degrees (clockwise). 显然的,矩阵旋转. 这里我是多开一个数组来直接赋值,没有原地翻转. 或许原地翻转能更快. package leetcode.…

原题地址:https://oj.leetcode.com/problems/rotate-list/ 题意: Given a list, rotate the list to the right by k places, where k is non-negative. For example:Given 1->2->3->4->5->NULL and k = 2,return 4->5->1->2->3->NULL. 解题思路:循环右移一条链表…

原题地址:https://oj.leetcode.com/problems/rotate-image/ 题意: You are given an n x n 2D matrix representing an image. Rotate the image by 90 degrees (clockwise). Follow up:Could you do this in-place? 解题思路:先将矩阵转置,然后将矩阵的每一行翻转,就可以得到所要求的矩阵了. 代码: class Solution…

Rotate Array 本题目收获: 题目: Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. 思路: 我的思路:新建一个数组存放旋转后的内容,但是怎么把原数组的内容存放在数组中,不清楚. leetcode/discuss思路: 思路一:新建数组,复制原…

Given an array of integers A and let n to be its length. Assume Bk to be an array obtained by rotating the array A k positions clock-wise, we define a "rotation function" F on A as follow: F(k) = 0 * Bk[0] + 1 * Bk[1] + ... + (n-1) * Bk[n-1]. Ca…

You are given an n x n 2D matrix representing an image. Rotate the image by 90 degrees (clockwise). Follow up: Could you do this in-place? Do not think too much about this problem, don't be scared by the "Matrix" word. This problem can be done i…

  问题: You are given an n x n 2D matrix representing an image. Rotate the image by 90 degrees (clockwise). Follow up: Could you do this in-place?   分析: 二维数组a[n][n]顺时针旋转90度,要解决这个问题,无疑,第一件事儿就是找规律. 当n=1时,不用动了. 当n=2时, 旋转之后变为 有: a[0][0] = a[1][0] a[1][0] =…

in place交换 如果是k步,那么就是把后面k个放到前面了嘛. 我们先把整个数组reverse,然后把前面的reverse回来,再把后面的reverse回来 对于AB我们要通过reverse操作得到BA 那么先把AB reverse一次得到reverse(B)reverse(A) 然后再把reverse(B),reverse(A)分别reverse一次就得到了BA class Solution { public: void rotate(int nums[], int n, int k) {…

题意: 将一个n*n的矩阵顺时针旋转90度. 思路: 都是差不多的思路,交换3次也行,反转再交换也是行的. class Solution { public: void rotate(vector<vector<int>>& matrix) { , n=matrix.size(); <n) { ; j++) { swap(matrix[n-j-][i],matrix[n-i-][n-j-]); swap(matrix[n-i-][n-j-],matrix[j][n-i-…

题目 You are given an n x n 2D matrix representing an image. Rotate the image by 90 degrees (clockwise). Follow up: Could you do this in-place? 原题链接(点我) 解题思路 顺时针方向旋转数组90°.这个题也是个没啥意思的题,自己画绘图,找找规律.就出来了.我举一个n=4的样例还说明下规律: 通过图能够看出A[0][0] = A[3][0],.....从这些中…

We are given two strings, A and B. A shift on A consists of taking string A and moving the leftmost character to the rightmost position. For example, if A = 'abcde', then it will be 'bcdea' after one shift on A. Return True if and only if A can becom…

Rotate List Given a list, rotate the list to the right by k places, where k is non-negative. For example:Given 1->2->3->4->5->NULL and k = 2,return 4->5->1->2->3->NULL. SOLUTION 1: 重点就是,要先变成循环链表,end.next = head;再执行ListNode he…

Rotate ImageYou are given an n x n 2D matrix representing an image. Rotate the image by 90 degrees (clockwise). Follow up:Could you do this in-place? SOLUTION 1: 我们可以把它当作多个嵌套的环来处理,一环加一环.从外环处理到内环.为了方便处理各种下标,我们定义top, bottom, left, right来限制环的左右上下边界. 1.…

1. Question You are given an n x n 2D matrix representing an image. Rotate the image by 90 degrees (clockwise). Note: You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matri…

You are given an n x n 2D matrix representing an image. Rotate the image by 90 degrees (clockwise). Follow up:Could you do this in-place? 方法一:常规思路: 将图片分为 行数/2 层,然后一层层进行旋转,由外到里.在这个过程中,比较关键的是下标的处理.可从n=3时得出一定的规律.每次旋转时,分析替换的元素对的下标和行.列的关系.如 i=0.j=0时 1:[0]…

题意:给定一个数组,将该数组的后k位移动到前n-k位之前.(本题在编程珠玑中第二章有讲) 思路: 方法一:将后K位用vector容器装起来,再移动前n-k位到后面,再将容器内k位插到前面. class Solution { public: void rotate(int nums[], int n, int k) { || k==n ) return; k %= n; vector<int> cha; cha.reserve(k); int i; for(i=n-k; i<n; i++)…

Given a list, rotate the list to the right by k places, where k is non-negative. For example:Given 1->2->3->4->5->NULL and k = 2,return 4->5->1->2->3->NULL. Hide Tags Linked List Two Pointers       这题有点难理解,k 的意思是链表右起第k 个,k 大于…

You are given an n x n 2D matrix representing an image. Rotate the image by 90 degrees (clockwise). Follow up:Could you do this in-place? Hide Tags Array   一题严格的数组逻辑操作问题,考虑认真就好,思路:   1 2 3 1 3 4 4 2 2 4 4 3 1 3 2 1 如上表,一共有两圈,对于n 来说,圈数为(n+1)/2,从外圈到内圈,…

问题描述: Given an array, rotate the array to the right by k steps, where k is non-negative. Example 1: Input: [1,2,3,4,5,6,7] and k = 3 Output: [5,6,7,1,2,3,4] Explanation: rotate 1 steps to the right: [7,1,2,3,4,5,6] rotate 2 steps to the right: [6,7,1…

struct ListNode { int val; ListNode *next; ListNode(int x) : val(x), next(NULL) {} }; class Solution { public: ListNode* rotateRight(ListNode* head, int k) { int level = -1; int size = 0; ListNode *ptr = head; while(ptr != nullptr) //一定要找到size,并取余,不然…

Given an array of integers A and let n to be its length. Assume Bk to be an array obtained by rotating the array A k positions clock-wise, we define a "rotation function" F on A as follow: F(k) = 0 * Bk[0] + 1 * Bk[1] + ... + (n-1) * Bk[n-1]. Ca…

题意: 将链表的后面k个剪出来,拼接到前面,比如 1->2->null 变成2->1->null.数字代表一段的意思. 思路: k有3种可能,k>n,k<n,k=n.理想情况就是k<n,这样就好操作,而当k>n时,k%=n即可,而当k=n时,无需操作.链表可能为空! /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListN…

We are given two strings, A and B. A shift on A consists of taking string A and moving the leftmost character to the rightmost position. For example, if A = 'abcde', then it will be 'bcdea' after one shift on A. Return True if and only if A can becom…

题目:rotate list 解法1: <span style="font-size:18px;">/**LeetCode Rotate List:Given a list, rotate the list to the right by k places, where k is non-negative. * 题目:循环移动链表,等价于将链表从右边数的k个节点移动到表的前方 * 思路:移动倒是简单.重点是要找到链表倒数的k个数,就等价于找到倒数第K+1个数,设置两个指针,…

最近在准备找工作的算法题,刷刷LeetCode,以下是我的解题报告索引,每一题几乎都有详细的说明,供各位码农参考.根据我自己做的进度持续更新中......                              本文地址 LeetCode:Reverse Words in a String LeetCode:Evaluate Reverse Polish Notation LeetCode:Max Points on a Line LeetCode:Sort List LeetCode:Ins…