LeetCode——Summary Ranges】的更多相关文章

Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. Credits:Special thanks to @jianchao.li.fighter for adding this problem and…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 思想很简单 逐个比较前后两个数的差值. class Solution { public: vector<string> summaryR…
Description: Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 确定有序数组的区间 需要注意各种边界细节,每次确定区间之后需要清空. public class Solution { pu…
Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Explanation: 0,1,2 form a continuous range; 4,5 form a continuous range. Exa…
题意:给出个有序不重复数列(可能负数),用缩写法记录这个数列. 思路:找每个范围的起始和结束即可. class Solution { public: vector<string> summaryRanges(vector<int>& nums) { if(nums.empty()) return vector<string>(); vector<string> vect; ; i<nums.size(); i++) { int s=nums[i…
1 题目 Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 接口:public List<String> summaryRanges(int[] nums); 2 思路 给定一个排序好的…
[LeetCode]228. Summary Ranges 解题报告(Python) 标签(空格分隔): LeetCode 题目地址:https://leetcode.com/problems/summary-ranges/description/ 题目描述: Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Outp…
Summary Ranges Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Explanation: 0,1,2 form a continuous range; 4,5 form a contin…
Given a sorted integer array where the range of elements are [0, 99] inclusive, return its missing ranges.For example, given [0, 1, 3, 50, 75], return [“2”, “4->49”, “51->74”, “76->99”] 这道题让我们求缺失区间,跟之前那道Summary Ranges很类似,这道题让我们求缺失的空间,给了一个空间的范围[lo…
题目: 228. Summary Ranges Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 答案: 就是找连续的序列. 直接判断相邻数据大小是否相差为1即可,主要是注意最后的数字要特殊考虑一下…
原题链接在这里:https://leetcode.com/problems/missing-ranges/ 题目: Given a sorted integer array where the range of elements are [lower, upper] inclusive, return its missing ranges. For example, given [0, 1, 3, 50, 75], lower = 0 and upper = 99, return ["2&quo…
Missing Ranges Given a sorted integer array where the range of elements are [lower, upper] inclusive, return its missing ranges. For example, given [0, 1, 3, 50, 75], lower = 0 and upper = 99, return ["2", "4->49", "51->74&q…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 我的代码,结果Accepted,507ms: public class Solution { public IList<string>…
Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Example 2: Input: [0,2,3,4,6,8,9] Output: ["0","2->4"…
Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Explanation: 0,1,2 form a continuous range; 4,5 form a continuous range. Exa…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 解题思路: JAVA实现如下: public List<String> summaryRanges(int[] nums) { List…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. class Solution { public: vector<string> summaryRanges(vector<int&…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. Credits:Special thanks to @jianchao.li.fighter for adding this problem and…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 分析:题意为 给定一个有序整型数组,返回总结区间,具体来说就是找出连续的序列,然后首尾两个数字之间用个“->"来连接,那么只需遍历一…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. My Solution: vector<string> summaryRanges(vector<int>& num…
题目描述: Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 解题思路: 相邻的两个数字若差距为1,则继续向后读,直到不满足条件为止,则把起始到终点的结果表示出来.如此,直到读到数组的最后位置为止.…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 题目大意:给一个有序数组,返回连续的区间范围. public class Solution { public List<String>…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. Credits:Special thanks to @jianchao.li.fighter for adding this problem and…
问题描述: Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 给定一个排好序的数组,用区间范围进行概括该数组后,返回新的区间范围数组. 算法: //返回范围 public static List&l…
Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Explanation: 0,1,2 form a continuous range; 4,5 form a continuous range. Exa…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 就是概括区间的方式把一个数组表示下来,例如123用1->3代替,自己写的很乱 ,维护两个指针就可以了: class Solution { pu…
题目 Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 分析 题目要求很明显,要求对给定的一组有序整数序列按照连续性分组显示: 一次遍历记录连续子序列的首尾元素,然后转换为string格式,整数和字…
vector<string> summaryRanges(vector<int>& nums) { int nums_len = nums.size(); vector<string> res; ) return res; ; i < nums_len;) { int start = i, end = i; < nums_len && nums[end + ] == nums[end] + ) end++; if (end >…
Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Explanation: 0,1,2 form a continuous range; 4,5 form a continuous range. Exa…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. class Solution { public: vector<string> summaryRanges(vector<int&…