ZOJ3708:Density of Power Network】的更多相关文章

The vast power system is the most complicated man-made system and the greatest engineering innovation in the 20th century. The following diagram shows a typical 14 bus power system. In real world, the power system may contains hundreds of buses and t…
The vast power system is the most complicated man-made system and the greatest engineering innovation in the 20th century. The following diagram shows a typical 14 bus power system. In real world, the power system may contains hundreds of buses and t…
Problem The vast power system is the most complicated man-made system and the greatest engineering innovation in the 20th century. The following diagram shows a typical 14 bus power system. In real world, the power system may contains hundreds of bus…
/*看英文和图我头都大了,不过很简单的.*/ #include<string.h> #include<stdio.h> ][],q[],w[]; int main(int argc, char* argv[]) { int t,n,m,i,j; int count; scanf("%d",&t); while(t--) { memset(s,,sizeof(s)); count=; scanf("%d%d",&n,&m…
http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3708 #include <stdio.h> #include <string.h> int main(int argc, char *argv[]) { int T,i,j,lineSum; int N,M; int x[505],y[505]; int lineL [505][505] ; scanf("%d",&T); for…
Description A power network consists of nodes (power stations, consumers and dispatchers) connected by power transport lines. A node u may be supplied with an amount s(u) >= 0 of power, may produce an amount 0 <= p(u) <= p max(u) of power, may co…
Power Network Time Limit: 2000MS   Memory Limit: 32768K Total Submissions: 24019   Accepted: 12540 Description A power network consists of nodes (power stations, consumers and dispatchers) connected by power transport lines. A node u may be supplied…
Power Network Time Limit: 2000MS Memory Limit: 32768K Total Submissions: 24867 Accepted: 12958 Description A power network consists of nodes (power stations, consumers and dispatchers) connected by power transport lines. A node u may be supplied with…
                                     Power Network Time Limit: 2000MS   Memory Limit: 32768K Total Submissions: 27229   Accepted: 14151 Description A power network consists of nodes (power stations, consumers and dispatchers) connected by power trans…
点击打开链接 Power Network Time Limit: 2000MS   Memory Limit: 32768K Total Submissions: 20903   Accepted: 10960 Description A power network consists of nodes (power stations, consumers and dispatchers) connected by power transport lines. A node u may be su…
题目连接 http://poj.org/problem?id=1459 Power Network Description A power network consists of nodes (power stations, consumers and dispatchers) connected by power transport lines. A node u may be supplied with an amount s(u) >= 0 of power, may produce an…
Power Network Time Limit: 2000MS   Memory Limit: 32768K Total Submissions: 25514   Accepted: 13287 Description A power network consists of nodes (power stations, consumers and dispatchers) connected by power transport lines. A node u may be supplied…
Time Limit: 2000MS   Memory Limit: 32768K Total Submissions: 20754   Accepted: 10872 Description A power network consists of nodes (power stations, consumers and dispatchers) connected by power transport lines. A node u may be supplied with an amount…
Power Network Time Limit: 2000MS   Memory Limit: 32768K Total Submissions: 22987   Accepted: 12039 Description A power network consists of nodes (power stations, consumers and dispatchers) connected by power transport lines. A node u may be supplied…
原题链接 题意简述 原题看了好几遍才看懂- 给出一个个点,条边的有向图.个点中有个源点,个汇点,每个源点和汇点都有流出上限和流入上限.求最大流. 题解 建一个真 · 源点和一个真 · 汇点.真 · 源点向所有原源点连容量等于其上限的边,所有原汇点向真 · 汇点连容量等于其上限的边.跑一遍最大流即可. Code //Power Network #include <cstdio> #include <cstring> #include <algorithm> using n…
POJ 1459 Power Network / HIT 1228 Power Network / UVAlive 2760 Power Network / ZOJ 1734 Power Network / FZU 1161 (网络流,最大流) Description A power network consists of nodes (power stations, consumers and dispatchers) connected by power transport lines. A…
Power Network Time Limit: 2000MS Memory Limit: 32768K Description A power network consists of nodes (power stations, consumers and dispatchers) connected by power transport lines. A node u may be supplied with an amount s(u) >= 0 of power, may produc…
Language: Default Power Network Time Limit: 2000MS   Memory Limit: 32768K Total Submissions: 23407   Accepted: 12267 Description A power network consists of nodes (power stations, consumers and dispatchers) connected by power transport lines. A node…
Power Network Time Limit: 2000MS   Memory Limit: 32768K Total Submissions: 31086   Accepted: 15986 题目链接:http://poj.org/problem?id=1459 Description: A power network consists of nodes (power stations, consumers and dispatchers) connected by power trans…
  Time Limit: 2000MS   Memory Limit: 32768K Total Submissions: 24788   Accepted: 12922 Description A power network consists of nodes (power stations, consumers and dispatchers) connected by power transport lines. A node u may be supplied with an amou…
题目链接:https://vjudge.net/problem/POJ-1459 Power Network Time Limit: 2000MS   Memory Limit: 32768K Total Submissions: 29270   Accepted: 15191 Description A power network consists of nodes (power stations, consumers and dispatchers) connected by power t…
Power Network Time Limit: 2000MS   Memory Limit: 32768K Total Submissions: 25414   Accepted: 13247 Description A power network consists of nodes (power stations, consumers and dispatchers) connected by power transport lines. A node u may be supplied…
#include<cstdio> #include<cstring> #include<algorithm> #include<queue> #include<vector> #define INF 1e9 using namespace std; const int maxn=100+5; struct Edge { int from,to,cap,flow; Edge(){} Edge(int f,int t,int c,int fl):fr…
Power Network Time Limit: 2000MS   Memory Limit: 32768K Total Submissions: 27282   Accepted: 14179 Description A power network consists of nodes (power stations, consumers and dispatchers) connected by power transport lines. A node u may be supplied…
读题比做题难系列…… poj1087 输入n,代表插座个数,接下来分别输入n个插座,字母表示.把插座看做最大流源点,连接到一个点做最大源点,流量为1. 输入m,代表电器个数,接下来分别输入m个电器,字符串表示.把电器看做最大流终点,连接到一个点做最大汇点,流量为1. 输入k,代表转换器个数,接下来分别输入k个转换器,每个插座输入两个字母a,b表示a可以连在b上.把转换器看做流,b->a,因为转换器无限提供,流量为无限大 代码: #include <iostream> #include &…
http://poj.org/problem?id=1459 题意:有np个发电站,nc个消费者,m条边,边有容量限制,发电站有产能上限,消费者有需求上限问最大流量. 思路:S和发电站相连,边权是产能上限,消费者和T相连,边权是需求上限,边的话就按题意加就好了.难点更觉得在于输入..加个空格..边数组要*2,因为有反向边. #include <cstdio> #include <algorithm> #include <iostream> #include <cs…
题意:给出n,np,nc,m,n为节点数,np为发电站数,nc为用电厂数,m为边的个数.      接下来给出m个数据(u,v)z,表示w(u,v)允许传输的最大电力为z:np个数据(u)z,表示发电站的序号,以及最大的发电量:      nc个数据(u)z,表示用电厂的序号,以及最大的用电量.      最后让你求可以供整个网络使用的最大电力.思路:纯模板题.      这里主要是设一个源点s和一个汇点t,s与所有发电厂相连,边的最大容量为对应发电厂的最大发电量:      t与所有用电厂相连…
题目:http://poj.org/problem?id=1459 题意:有一些发电站,消耗用户和中间线路,求最大流.. 加一个源点,再加一个汇点.. 其实,过程还是不大理解.. #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <queue> using namespace std; <<; ][],flow[…
题目链接: http://poj.org/problem?id=1459 因为发电站有多个,所以需要一个超级源点,消费者有多个,需要一个超级汇点,这样超级源点到发电站的权值就是发电站的容量,也就是题目中的pmax,消费者到超级汇点的权值就是消费者的容量,也就是题目中的cmax.初学网络流,第一眼看到这个题还以为应该先做一遍EK算法,然后减去max(p-pmax, c-cmax)呢..没想到这个题的难点就是建图而已.. #include <stdio.h> #include <string…
题目大意:题目说了一大堆,其实都是废话......让人有些不知所云,其实就是给了一些电厂,和一些消费点,然后里面有一些路线什么的,求出消费点可以最多消费的电量是多少. 输入大意: 分析:懂了题意就是一个模板...还不用拆点什么的,不过输入的时候不太明白为什么scanf("(%d,%d)%d")这种输入不好使了,只得用字符串直接读的. 下面是AC代码. #include<stdio.h> #include<; ; ; s[i]; i++)     {         }…