题意: 莫名其妙 看不懂..只能靠别人的题意混日子 a完就懂了  就是 POJ1392  不求第k个了  直接输出这个路径 emm ...就改了一下那个代码 #include <iostream> #include <cstdio> #include <sstream> #include <cstring> #include <map> #include <cctype> #include <set> #include &…

Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 1424    Accepted Submission(s): 469 Problem Description     Holion August will eat every thing he has found. Now there are many foods,bu…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1715 大菲波数 Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 22523    Accepted Submission(s): 8096 Problem Description Fibonacci数列,定义如下:f(1)=f(2)=1f(…

题目链接:http://acm.hdu.edu.cn/listproblem.php?vol=44 题意:给你n个n,如果能在n-1次运算之后(加减乘除)结果为24的输出n-1次运算的过程,如果不能输出-1. 思路:乍看起来,没什么规律,但是可以想象的是(n+n+n+n)/n=4,(n+n+n+n+n+n)/n=6,(n-n)*n*n*·····*n=0所以在n大于15的时候结果基本是固定的,只要对小于15的数一一输出就行(但是这题真是无语,算这种题目真是累,脑洞啊~~) 代码: #includ…

题目地址:pid=4920">HDU 4920 对这个题简直无语到极点. . .竟然O(n^3)的复杂度能过....方法有三.. 1:进行输入优化和输出优化. . (前提是你的输入优化不能太搓...) 2:利用缓存优化..详情请看该论文.大体就是将后两个for循环换过来,让坐标改变的频率降下来. 3:叉姐题解中说的正规方法. .利用biset存储,进行预处理. .(事实上我还没看懂.. 我仅仅写了个另外一种.. .代码例如以下.共勉..奇妙的小代码.. #include <iostr…

开门人和关门人 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 11133    Accepted Submission(s): 5667 Problem Description 每天第一个到机房的人要把门打开.最后一个离开的人要把门关好.现有一堆杂乱的机房签  到.签离记录,请依据记录找出当天开门和关门的人.    Input 測试输…

传送门: http://acm.hdu.edu.cn/showproblem.php?pid=2072 单词数 Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 63805    Accepted Submission(s): 15912 Problem Description lily的好朋友xiaoou333最近很空,他想了一件没有什么…

Random Maze Time Limit: 10000/3000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1669    Accepted Submission(s): 682 Problem Description In the game “A Chinese Ghost Story”, there are many random mazes which have s…

Go Deeper Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 3435    Accepted Submission(s): 1125 Problem Description Here is a procedure's pseudocode: go(int dep, int n, int m)beginoutput the valu…

题目大意:给你L到N的范围,要求你求这个范围内的所有整数的立方和. Sample Input2 //T1 32 5 Sample OutputCase #1: 36Case #2: 224 # include <iostream> # include <cstdio> # include <cstring> # include <algorithm> # include <cmath> # define LL long long using na…