网址:https://leetcode.com/problems/binary-prefix-divisible-by-5/ 一次for循环遍历数组,在上次计算的基础上得到本次的结果! class Solution { public: vector<bool> prefixesDivBy5(vector<int>& A) { vector<bool> ans; ; ; ; i<A.size(); i++) { num = ; num += pre_num…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/binary-prefix-divisible-by-5/ 题目描述 Given an array A of 0s and 1s, consider N_i: the i-th subarray from ```A[0]toA[i]`` interpreted as a bi…

题目如下: Given an array A of 0s and 1s, consider N_i: the i-th subarray from A[0] to A[i] interpreted as a binary number (from most-significant-bit to least-significant-bit.) Return a list of booleans answer, where answer[i]is true if and only if N_i is…

class Solution: def prefixesDivBy5(self, A: List[int]) -> List[bool]: ans,t = [],0 for a in A: t = (t * 2 + a)%5 ans.append(False if t else True) return ans…

Given an array A of 0s and 1s, consider N_i: the i-th subarray from A[0] to A[i] interpreted as a binary number (from most-significant-bit to least-significant-bit.) Return a list of booleans answer, where answer[i] is true if and only if N_i is divi…

Given an array A of 0s and 1s, consider N_i: the i-th subarray from A[0] to A[i] interpreted as a binary number (from most-significant-bit to least-significant-bit.) Return a list of booleans answer, where answer[i] is true if and only if N_i is divi…

这是小川的第379次更新,第407篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第241题(顺位题号是1018).给定0和1的数组A,考虑N_i:从A[0]到A[i]的第i个子数组被解释为二进制数(从最高有效位到最低有效位). 返回布尔值answer列表,当且仅当N_i可被5整除时,answer[i]为true. 例如: 输入:[0,1,1] 输出:[true,false,false] 说明:二进制输入数字为0,01,011,转为十进制数,分别为0,1和3.只有第一…

CJOJ 1976 二叉苹果树 / URAL 1018 Binary Apple Tree(树型动态规划) Description 有一棵苹果树,如果树枝有分叉,一定是分2叉(就是说没有只有1个儿子的结点)这棵树共有N个结点(叶子点或者树枝分叉点),编号为1-N,树根编号一定是1.我们用一根树枝两端连接的结点的编号来描述一根树枝的位置.现在这颗树枝条太多了,需要剪枝.但是一些树枝上长有苹果. 给定需要保留的树枝数量,求出最多能留住多少苹果.下面是一颗有 4 个树枝的树. 2 5 \ / 3 4…

1018. Binary Apple Tree Time limit: 1.0 secondMemory limit: 64 MB Let's imagine how apple tree looks in binary computer world. You're right, it looks just like a binary tree, i.e. any biparous branch splits up to exactly two new branches. We will enu…

Let's imagine how apple tree looks in binary computer world. You're right, it looks just like a binary tree, i.e. any biparous branch splits up to exactly two new branches. We will enumerate by integers the root of binary apple tree, points of branch…