以此图为例: package com.datastruct; import java.util.Scanner; public class TestKruskal { private static class Edge{ public Edge(int begin,int end,int weight){ this.begin = begin; this.end = end; this.weight = weight; } int begin; int end; int weight; publ…
poj 1251 Jungle Roads (最小生成树) Link: http://poj.org/problem?id=1251 Jungle Roads Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 23507 Accepted: 11012 Description The Head Elder of the tropical island of Lagrishan has a problem. A b…
对于一个给定的连通的无向图 G = (V, E),希望找到一个无回路的子集 T,T 是 E 的子集,它连接了所有的顶点,且其权值之和为最小. 因为 T 无回路且连接所有的顶点,所以它必然是一棵树,称为生成树(Spanning Tree),因为它生成了图 G.显然,由于树 T 连接了所有的顶点,所以树 T 有 V - 1 条边.一张图 G 可以有很多棵生成树,而把确定权值最小的树 T 的问题称为最小生成树问题(Minimum Spanning Tree).术语 "最小生成树" 实际上是…
最近在复习数据结构,所以想起了之前做的一个最小生成树算法.用Kruskal算法实现的,结合堆排序可以复习回顾数据结构.现在写出来与大家分享. 最小生成树算法思想:书上说的是在一给定的无向图G = (V, E) 中,(u, v) 代表连接顶点 u 与顶点 v 的边(即),而 w(u, v) 代表此边的权重,若存在 T 为 E 的子集(即)且为无循环图,使得的 w(T) 最小,则此 T 为 G 的最小生成树.说白了其实就是在含有 n 个顶点的连通网中选择 n-1 条边,构成一棵极小连通子图,并使该连…
Qin Shi Huang's National Road System Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6137 Accepted Submission(s): 2143 Problem Description During the Warring States Period of ancient China(47…
//归并排序递归方法实现 #include <iostream> #include <cstdio> using namespace std; #define maxn 1000005 int a[maxn], temp[maxn]; long long ans; void MergeSort(int a[], int l, int mid, int r) { ; int i = l, n = mid, j = mid, m = r; while ( i<n &&am…
The Unique MST Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 28207 Accepted: 10073 Description Given a connected undirected graph, tell if its minimum spanning tree is unique. Definition 1 (Spanning Tree): Consider a connected, undir…
Arctic Network Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 17758 Accepted: 5646 Description The Department of National Defence (DND) wishes to connect several northern outposts by a wireless network. Two different communication tec…