The nth term of the sequence of triangle numbers is given by, tn = ½n(n+1); so the first ten triangle numbers are: 1, 3, 6, 10, 15, 21, 28, 36, 45, 55, ... By converting each letter in a word to a number corresponding to its alphabetical position and…
Triangle, square, pentagonal, hexagonal, heptagonal, and octagonal numbers are all figurate (polygonal) numbers and are generated by the following formulae: Triangle   P3,n=n(n+1)/2   1, 3, 6, 10, 15, ... Square   P4,n=n2   1, 4, 9, 16, 25, ... Penta…
题意:三角形数序列的第n项由公式tn = 1/2n(n+1)给出:因此前十个三角形数是: 1, 3, 6, 10, 15, 21, 28, 36, 45, 55, - 将一个单词的每个字母分别转化为其在字母表中的顺序并相加,我们可以计算出一个单词的值.求在words.txt中有多少个三角形单词? euler042.c /************************************************************************* > File Name: eu…
If we take 47, reverse and add, 47 + 74 = 121, which is palindromic. Not all numbers produce palindromes so quickly. For example, 349 + 943 = 1292, 1292 + 2921 = 4213 4213 + 3124 = 7337 That is, 349 took three iterations to arrive at a palindrome. Al…
A natural number, N, that can be written as the sum and product of a given set of at least two natural numbers, {a1, a2, ... , ak} is called a product-sum number: N = a1 + a2 + ... + ak = a1 × a2 × ... × ak. For example, 6 = 1 + 2 + 3 = 1 × 2 × 3. Fo…
The smallest number expressible as the sum of a prime square, prime cube, and prime fourth power is 28. In fact, there are exactly four numbers below fifty that can be expressed in such a way: 28 = 22 + 23 + 24 33 = 32 + 23 + 24 49 = 52 + 23 + 24 47…
For a number written in Roman numerals to be considered valid there are basic rules which must be followed. Even though the rules allow some numbers to be expressed in more than one way there is always a "best" way of writing a particular number…
By using each of the digits from the set, {1, 2, 3, 4}, exactly once, and making use of the four arithmetic operations (+, −, *, /) and brackets/parentheses, it is possible to form different positive integer targets. For example, 8 = (4 * (1 + 3)) /…
Starting with 1 and spiralling anticlockwise in the following way, a square spiral with side length 7 is formed. 37 36 35 34 33 32 31 38 17 16 15 14 13 30 39 18  5  4  3 12 29 40 19  6  1  2 11 28 41 20  7  8  9 10 27 42 21 22 23 24 25 26 43 44 45 46…
If p is the perimeter of a right angle triangle with integral length sides, {a,b,c}, there are exactly three solutions for p = 120. {20,48,52}, {24,45,51}, {30,40,50} For which value of p ≤ 1000, is the number of solutions maximised? #include <iostre…