【leetcode】280.Wiggle Sort】的更多相关文章

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 排序后交换相邻元素 日期 题目地址:https://leetcode-cn.com/problems/wiggle-sort/ 题目描述 Given an unsorted array nums, reorder it in-place such that nums[0] <= nums[1] >= nums[2] <= nums[3]....…
原题 Given an unsorted array nums, reorder it in-place such that nums[0] <= nums[1] >= nums[2] <= nums[3].... For example, given nums = [3, 5, 2, 1, 6, 4], one possible answer is [1, 6, 2, 5, 3, 4]. 解析 摇摆排序 只要奇数位上的数比左右偶数位上的数都大即可 思路 贪心算法:在对问题求解时,总是做…
[LeetCode]376. Wiggle Subsequence 解题报告(Python) 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址: https://leetcode.com/problems/wiggle-subsequence/description/ 题目描述: A sequence of numbers is called a wiggle sequence if the differences betw…
[LeetCode]147. Insertion Sort List 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/insertion-sort-list/description/ 题目描述: Sort a linked list using insertion sort. A graphical…
Sort a linked list using insertion sort. 链表的插入排序. 需要创建一个虚拟节点.注意点就是不要节点之间断了. class Solution { public: ListNode* insertionSortList(ListNode* head) { if(head==NULL||head->next==NULL) return head; ListNode* newhead = ); newhead->next=head; ListNode* q=h…
Description: A sequence of numbers is called a wiggle sequence if the differences between successive numbers strictly alternate between positive and negative. The first difference (if one exists) may be either positive or negative. A sequence with fe…
题目如下: Given two arrays arr1 and arr2, the elements of arr2 are distinct, and all elements in arr2 are also in arr1. Sort the elements of arr1 such that the relative ordering of items in arr1 are the same as in arr2.  Elements that don't appear in arr…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 按顺序构造字符串 排序 日期 题目地址:https://leetcode.com/problems/custom-sort-string/description/ 题目描述 S and T are strings composed of lowercase letters. In S, no letter occurs more than once.…
题目如下: 解题思路:本题和[leetcode]75. Sort Colors类似,但是没有要求在输入数组本身修改,所以难度降低了.引入一个新的数组,然后遍历输入数组,如果数组元素是是偶数,插入到新数组头部,否则追加到尾部. 代码如下: class Solution(object): def sortArrayByParity(self, A): """ :type A: List[int] :rtype: List[int] """ res =…
Wiggle Sort: 注意:解法一是每次i增加2,题目不是保证3个3个的情况,而是整个数组都要满足要求. 解法一错误版本: 如果nums的长度是4,这种情况下nums[i+1]会越界.但是如果你用的是i和i-1的组合,一定可以不会越界,因为i不越界i-1就一定不会越界,for循环控制i,i越界了整个循环就结束了. class Solution { public: void wiggleSort(vector<int>& nums) { sort(nums.begin(),nums.…