A string S of lowercase letters is given. Then, we may make any number of moves. In each move, we choose one of the first K letters (starting from the left), remove it, and place it at the end of the string. Return the lexicographically smallest str…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址: https://leetcode.com/problems/orderly-queue/description/ 题目描述: A string S of lowercase letters is given. Then, we may make any number of moves. In each move, we choose one of the first K l…
A string S of lowercase letters is given. Then, we may make any number of moves. In each move, we choose one of the first K letters (starting from the left), remove it, and place it at the end of the string. Return the lexicographically smallest str…
Design your implementation of the circular queue. The circular queue is a linear data structure in which the operations are performed based on FIFO (First In First Out) principle and the last position is connected back to the first position to make a…
Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of queue. pop() -- Removes the element from in front of queue. peek() -- Get the front element. empty() -- Return whether the queue is empty. Notes: You…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/queue-reconstruction-by-height/#/description 题目描述 Suppose you have a random list of people standing in a queue. Each person is described b…
Stack<Integer> stack=new Stack<Integer>(); public void push(int x) { stack.push(x); } // Removes the element from in front of queue. public void pop() { stack.remove(0); } // Get the front element. public int peek() { return stack.get(0); } //…
本题用两个栈实现队列,用栈的基本操作去实现队列的所有基本操作push(),pop(),peek()以及empty() sa作为输入栈,sb作为输出栈,将sa输入元素的反转过来放到sb中 push与sa有关,而pop(),peek()与sb有关,即将sa输入元素出栈放到sb中(函数move). 为此,只有两个栈为空才能让队列为空 class Queue { public: // Push element x to the back of queue. stack<int> sa; stack&l…
Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of queue. pop() -- Removes the element from in front of queue. peek() -- Get the front element. empty() -- Return whether the queue is empty. Notes: You…
