leetcode-55. Jump Game - Medium descrition Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Determine if you are abl…

Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Determine if you are able to reach the last index. Example 1: Input…

主要有两种思路: 一. 本题只需要判断能否到达最后一个数,那么可以采用贪心策略,到达某个位置i后,在直接在这个位置的基础上走nums[i]步,主要保证能一直前进,就能达到终点: 那么,什么时候才不能一直前进呢? 答案是,遇到0的时候,遇到nums[i]=0的时候,只要我们想办法跳过这个0,那么就可以确保我们可以继续前进. 所以遇到0时的处理方法是,往回搜索,设当前的位置为pos,即nums[pos]=0,一直搜索之前的数,判断nums[i]+i是否大于nums[pos],大于则可以继续上述的贪心…

Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Your goal is to reach the last index in the minimum number of jumps…

请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…

Dynamic Programming 实际上是[LeetCode] 系统刷题4_Binary Tree & Divide and Conquer的基础上,加上记忆化的过程.就是说,如果这个题目实际上是类似于Divide and conquer或者说是DFS,但是在计算过程中有很多重复计算同样的过程的话,那么就可以用Dynamic prgramming/记忆化搜索来完成.基本就是利用空间来简化时间复杂度的过程. 可以/很有可能使用Dynamic programming的条件,满足之一即可. 1.…

Note: 后面数字n表明刷的第n + 1遍, 如果题目有**, 表明有待总结 Conclusion questions: [LeetCode] questions conclustion_BFS, DFS LeetCode questions conclustion_Path in Tree [LeetCode] questions conlusion_InOrder, PreOrder, PostOrder traversal [LeetCode] questions for Dynamic…

Questions: [LeetCode] 198. House Robber _Easy tag: Dynamic Programming [LeetCode] 221. Maximal Square _ Medium Tag: Dynamic Programming [LeetCode] 62. Unique Paths_ Medium tag: Dynamic Programming [LeetCode] 64. Minimum Path Sum_Medium tag: Dynamic P…

All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) .   Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 把自己刷过的所有题目做一个整理,并且用简洁的语言概括了一下思路,汇总成了一个表格. 题目的排列顺序是按照先Easy再Medium再Hard排列的,暂时还没有把题目全部整理完成.后序我会把刷过的所有的题目都整理到这个文档里. 题目 难度 解法 题目地址 566. Reshape the Matrix Easy 变长数组,求余法,维护行列计算在新的数组中的位置 https://blog.c…

1. 原题链接 https://leetcode.com/problems/jump-game/description/ 2. 题目要求 给定一个整型数组,数组中没有负数.从第一个元素开始,每个元素的值代表每一次你能从当前位置跳跃的步数.问能否跳到该数组的最后一个元素位置 注意:可以跳的步数超出数组长度依旧视为可以达到最后位置 3. 解题思路 从第一个元素开始遍历,记录下你所能到达的最远位置,例如{2, 2, 0, 1, 2},遍历第一个元素时,你所能到达的最远位置是“i+nums[i]”=2,…

原题 题目意思即 每一格代表你当前最多能再往后跳几次,从第一格开始,如果能跳到最后一格返回true,反之为false. 思路:用一个下标记录当前最多能跳到哪一格,遍历一遍 --> 如果当前格子不在可以跳到的范围内,则跳出遍历 --> 如果最多能跳到格子长度大于数组长度,则为true: /** * @param {number[]} nums * @return {boolean} */ var canJump = function(nums) { var rightIndex = 1; for…

55. Jump Game Total Accepted: 95819 Total Submissions: 330538 Difficulty: Medium Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at t…

http://shazwazza.com/post/Developing-a-plugin-framework-in-ASPNET-with-medium-trust.aspx January 7, 2011 10:06 Tweet I’ve recently spent quite a lot of time researching and prototyping different ways to create a plugin engine in ASP.NET MVC3 and prim…

题目:跳跳游戏 难度:Medium 题目内容: Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Determine if you are able to reach the last…

Level:   Medium 题目描述: Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Determine if you are able to reach the last i…

一.题目说明 题目55. Jump Game,给定一组非负数,从第1个元素起,nums[i]表示你当前可以跳跃的最大值,计算能否到达最后一个index.难度是Medium. 二.我的解答 非常惭愧,这个题目我做完,提交n次,除了几次边界错,其他就是Time Limit Exceeded,而且优化也无果. 我的代码: class Solution{ public: bool canJump(vector<int>& nums) { vector<bool> dp(nums.s…

A frog is crossing a river. The river is divided into x units and at each unit there may or may not exist a stone. The frog can jump on a stone, but it must not jump into the water. Given a list of stones' positions (in units) in sorted ascending ord…

Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Determine if you are able to reach the last index. For example:A = …

Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Your goal is to reach the last index in the minimum number of jumps…

Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Your goal is to reach the last index in the minimum number of jumps…

我一开始认为这是一道DP的题目.其实,可以维护一个maxReach,并对每个元素更新这个maxReach = max(maxReach, i + nums[i]).注意如果 i>maxReach,说明从起点开始能跳到的最远距离不到i, 所以i后面的点也就无法到达了.另外如果 maxReach >= n-1 说明已经可以跳到终点了,之后的点也就不用继续检查了. class Solution(object): def canJump(self, nums): """…

题目: Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Your goal is to reach the last index in the minimum number of j…

Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Your goal is to reach the last index in the minimum number of jumps…

Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Determine if you are able to reach the last index. For example:A = …

gdb或者vlagrind报告: ==14569== Jump to the invalid address stated on the next line ==14569== at 0x0: ??? ==14569== Address 0x0 is not stack'd, malloc'd or (recently) free'd 错误原因:函数通过jmp,call,ret等指令跳转到0x00,错误可能出现的范围 1.函数缓冲区溢出覆盖了返回地址,然后又调用了return,例如 #inclu…

Jump Game 是一道有意思的题目.题意很简单,给你一个数组,数组的每个元素表示你能前进的最大步数,最开始时你在第一个元素所在的位置,之后你可以前进,问能不能到达最后一个元素位置. 比如: A = [2, 3, 1, 1, 4], return true. 一种走法是 0 - 2 - 3 - 4,还有一种走法是 0 - 1 - 4 O(n ^ 2) 解法 一个很显然,几乎不用动脑的解法. 设置一个布尔数组f,f[0] === true 表示 index === 0 这个位置能够到达,模拟每个…

这文章会向你展示, 怎么配置ASP.NET Web应用程序, 使之运行在medium trust.   如果你的服务器有多个应用程序, 你可以使用code access security和medium trust级别去隔离应用程序   通过设置和锁定machine级别的Web.config的信任级别, 你可以为服务器的Web应用程序建立安全策略.   运行ASP.NET的medium trust, 2.0比1.1较容易的, 因为当使用ASP.NET 2.0, 你不得不访问MS SQL Serve…

A frog is crossing a river. The river is divided into x units and at each unit there may or may not exist a stone. The frog can jump on a stone, but it must not jump into the water. Given a list of stones' positions (in units) in sorted ascending ord…

Jump Game (middle) Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Determine if you are able to reach the last inde…