Given a 2D board and a list of words from the dictionary, find all words in the board. Each word must be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same le…

Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell may not be us…

July 6, 2015 Problem statement: Word Search Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically nei…

Word SearchGiven a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell ma…

超时,用了tire也不行,需要再改. class Solution { class TrieNode { public: // Initialize your data structure here. TrieNode() { for(int i=0;i<26;i++) next[i]=NULL; isString = false; } TrieNode *next[26]; bool isString; }; class Trie { public: Trie() { root = new T…

原题地址:https://oj.leetcode.com/problems/word-search/ 题意: Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or ver…

Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell may not be us…

题目 Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell may not be…

终于搞定了这个DFS,最近这个DFS写的很不顺手,我一直以为递归这种东西只是在解重构时比较麻烦,现在看来,连最简单的返回true和false的逻辑关系都不能说one hundred present 搞定. 人品啊TLE: class Solution { public: bool legal(int i, int j, vector<vector<char>> board) { && i < board.size() && j >= &a…

Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell may not be us…