Problem Description My birthday is coming up and traditionally I'm serving pie. Not just one pie, no, I have a number N of them, of various tastes and of various sizes. F of my friends are coming to my party and each of them gets a piece of pie. This…

题目大意:n块馅饼分给m+1个人,每个人的馅饼必须是整块的,不能拼接,求最大的. 解题思路: 1)用总饼的体积除以总人数,得到每个人最大可以得到的V.但是每个人手中不能有两片或多片拼成的一块饼. 代码如下: /* * 1969_2.cpp * * Created on: 2013年8月14日 * Author: Administrator */ #include <stdio.h> #include <math.h> #include <string.h> double…

Pie Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 16554    Accepted Submission(s): 5829   My birthday is coming up and traditionally I'm serving pie. Not just one pie, no, I have a number N of…

1.题意:一项分圆饼的任务,一堆圆饼共有N个,半径不同,厚度一样,要分给F+1个人.要求每个人分的一样多,圆饼允许切但是不允许拼接,也就是每个人拿到的最多是一个完整饼,或者一个被切掉一部分的饼,要求你算出每人能分到的饼的体积最大值.输入数据依次给出,测试数据组数T,每组数据中,给出N,F,以及N个圆饼的半径.输出最大体积的数值,精确到小数点后四位. 2.分析:一看是这种输出就知道用二分写会很高效,这里对"能分出的最大体积值"进行二分.首先,这个值有界,最大值为总体积除以总人数的值,即Σ…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1969 Pie Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4513    Accepted Submission(s): 1819 Problem Description My birthday is coming up and trad…

Problem Description My birthday is coming up and traditionally I'm serving pie. Not just one pie, no, I have a number N of them, of various tastes and of various sizes. F of my friends are coming to my party and each of them gets a piece of pie. This…

二分查找是一个非常主要的算法,针对的是有序的数列,通过中间值的大小来推断接下来查找的是左半段还是右半段,直到中间值的大小等于要找到的数时或者中间值满足一定的条件就返回,所以当有些问题要求在一定范围内找到一个满足一些约束的值时就能够用二分查找,时间复杂度O(log n); 题目:http://acm.hit.edu.cn/hoj/problem/view?id=2651 由于题目有精度要求,对于浮点数小数点部分会有一定误差,所以能够选择将这些有小数部分的数值扩大e6倍,由于题目要求精确到e-3,之…

Give you three sequences of numbers A, B, C, then we give you a number X. Now you need to calculate if you can find the three numbers Ai, Bj, Ck, which satisfy the formula Ai+Bj+Ck = X. Input There are many cases. Every data case is described as foll…

[分析] “虽然不是求什么最大的最小值(或者反过来)什么的……但还是可以用二分的,因为之前就做过一道小数型二分题(下面等会讲) 考虑二分面积,下界L=0,上界R=∑ni=1nπ∗ri2.对于一个中值x和一张半径r的饼来说,这张饼能够分出的最多分数显然是:⌊π∗r2x⌋,所以我们只需要求出∑ni=1⌊π∗ri2x⌋,判断其与f+1的关系即可 特别要注意的一点:π的大小!,因为r≤104r≤104,所以r2≤108r2≤108,又因为题目要求精确到三位小数,所以ππ就要精确到10-11,即π=3.1…

Pie Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 12138    Accepted Submission(s): 4280 Problem Description My birthday is coming up and traditionally I'm serving pie. Not just one pie, no, I…