解题思路:BFS 1)马的跳跃方向 在国际象棋的棋盘上,一匹马共有8个可能的跳跃方向,如图1所示,按顺时针分别记为1~8,设置一组坐标增量来描述这8个方向: 2)基本过程 设当前点(i,j),方向k,沿方向k跳一步后的新点(newi,newj):每走一步,都要判断新点(newi,newj)是否还在棋盘上: 若1£newi£8且1£newj£8,则新点仍在棋盘上,则还需判断该点是否已经走过,即 若visited[newi][newj]=0,表示该步可走: 若visited[newi][newj]=…

题目链接 Problem Description A friend of you is doing research on the Traveling Knight Problem (TKP) where you are to find the shortest closed tour of knight moves that visits each square of a given set of n squares on a chessboard exactly once. He think…

传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1372 Knight Moves Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 13384    Accepted Submission(s): 7831 Problem Description A friend of you is doin…

嗯... 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1372 这是一道很典型的bfs,跟马走日字一个道理,然后用dir数组确定骑士可以走的几个方向,然后从起点到终点跑一遍最典型的bfs即可...注意HDU的坑爹输入和输出... AC代码: #include<cstdio> #include<iostream> #include<queue> #include<cstring> using namespace…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1372 Knight Moves Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 10372    Accepted Submission(s): 6105 Problem Description A friend of you is doin…

题意:给出8*8的棋盘,给出起点和终点,问最少走几步到达终点. 因为骑士的走法和马的走法是一样的,走日字形(四个象限的横竖的日字形) 另外字母转换成坐标的时候仔细一点(因为这个WA了两次---@_@) #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<queue> #define maxn 105 using namespace s…

Knight Moves Time Limit: 2 Seconds      Memory Limit: 65536 KB A friend of you is doing research on the Traveling Knight Problem (TKP) where you are to find the shortest closed tour of knight moves that visits each square of a given set of n squares…

Problem Description A friend of you is doing research on the Traveling Knight Problem (TKP) where you are to find the shortest closed tour of knight moves that visits each square of a given set of n squares on a chessboard exactly once. He thinks tha…

最近在学习广搜  这道题同样是一道简单广搜题=0= 题意:(百度复制粘贴0.0) 题意:给出骑士的骑士位置和目标位置,计算骑士要走多少步 思路:首先要做这道题必须要理解国际象棋中骑士的走法,国际象棋中,骑士是在一个3*2的格子中进行对角线移动,通过画图很容易就知道骑士最多可以朝八个方向移动,那么就朝8个方向进行BFS即可 //细节注意: 1.输入开始结束坐标时需要保存  所以我用了全局变量  因为输出还需要他们=0=: 2.依旧是用bool类型进行map保存,防止内存超限, 0表示还未走过, 1…

Knight Moves Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 10542    Accepted Submission(s): 6211 Problem Description A friend of you is doing research on the Traveling Knight Problem (TKP) wh…